Inserting a substring value into an already existing entry

Currently I have a database with the following parameters and entry:

Now I want to fill the column status_from in this particular entry with the id 1 with a substring of the action column. Which is basically I want to fill my status_from column with a word that comes after from and before to of the action column. To achieve this I’ve tried using the following statement:

INSERT INTO crm_logs2(status_from) SELECT status_from WHERE id='1' VALUES (substring_index(substring_index(action, 'from', -1),'to', 1))

But doing this gave me the following error:

#1064 – You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ‘VALUES (substring_index(substring_index(action, ‘from’, -1), …’ at line 1

Answers:

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Method 1

You need to use the UPDATE statement

UPDATE crm_logs2 
SET status_from = (SUBSTRING_INDEX(SUBSTRING_INDEX(action, "from", -1), "to", 1))
WHERE id = 1

Method 2

update crm_logs2
set action=(select SUBSTRING_INDEX(SUBSTRING_INDEX(action, ' ', 6), ' ', -1) from 
crm_logs2 where id=1)where id=1

Try this and let us know if it works

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