MariaDB [test]> select * from Salesman;
| empId | name | gender | | 3 | Suresh Raina | M | | 4 | Surech Raina | M | | 5 | Surech Raina | F | | 11 | Andrew Flintoff | M | | 18 | Moeen Ali | M | | 45 | Rohit Sharma | M | MariaDB [test]> select * from Purchases; | clientId | empId | packageId | commissionRate | | 7 | 18 | 257 | 10.50 | | 18 | 11 | 183 | 4.50 | | 19 | 3 | 301 | 9.00 | | 55 | 45 | 110 | 8.00 |
These are the two tables I need help querying I need to display the salesman name and the avg commission rate in desc order of avg commission rate.
This is what I have so far but I think this is incorrect.
select name , avg(commissionRate) from Salesman natural JOIN Purchases order by avg(commissionRate) desc;
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It can be done with group by after joining tables :
select s.name , avg(p.commissionRate) from Purchases p inner JOIN Salesman s on s.empId=p.empId group by s.name order by 2 desc
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