What is the LIMIT clause alternative in JPQL?

I’m working with PostgreSQL query implementing in JPQL.

This is a sample native psql query which works fine,


The same query in JPQL doesnt work,

@Query("SELECT s FROM Students s ORDER BY s.id DESC LIMIT 1")

Students getLastStudentDetails();

seems like LIMIT clause doesn’t work in JPQL.

According to JPA documentation we can use setMaxResults/setFirstResult, Can anyone tell me how can I use that in my above query?


Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

You are using JPQL which doesn’t support limiting results like this. When using native JPQL you should use setMaxResults to limit the results.

However you are using Spring Data JPA which basically makes it pretty easy to do. See here in the reference guide on how to limit results based on a query. In your case the following, find method would do exactly what you want.


You could also use a Pageable argument with your query instead of a LIMIT clause.

@Query("SELECT s FROM Students s ORDER BY s.id DESC")
List<Students> getLastStudentDetails(Pageable pageable);

Then in your calling code do something like this (as explained here in the reference guide).


Both should yield the same result, without needing to resort to plain SQL.

Method 2

As stated in the comments, JPQL does not support the LIMIT keyword.

You can achieve that using the setMaxResults but if what you want is just a single item, then use the getSingleResult – it throws an exception if no item is found.

So, your query would be something like:

TypedQuery<Student> query = entityManager.createQuery("SELECT s FROM Students s ORDER BY s.id DESC", Student.class);    

If you want to set a specific start offset, use query.setFirstResult(initPosition); too

Method 3

Hello for fetching single row and using LIMIT in jpql we can tell the jpql if it’s a native query.

( using – nativeQuery=true )

Below is the use

@Query("SELECT s FROM Students s ORDER BY s.id DESC LIMIT 1", nativeQuery=true)
Students getLastStudentDetails();

Method 4

You can not use Limit in HQL because Limit is database vendor dependent so Hibernate doesn’t allow it through HQL query.

A way you can implement is using a subquery:

@Query("FROM Students st WHERE st.id = (SELECT max(s.id) FROM Students s)")
Students getLastStudentDetails();

Method 5

JPQL does not allow to add the limit keyword to the query generated by the HQL. You would get the following exception.

org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token:
LIMIT near line 1

But don’t worry there is an alternative to use the limit keyword in the query generated by the HQL by using the following steps.

Sort.by(sortBy).descending() // fetch the records in descending order

pageSize = 1 // fetch the first record from the descending order result set.

Refer the following service class


StudentRepository repository; 

public List<Student> getLastStudentDetails(Integer pageNo, Integer pageSize, String sortBy)
    Integer pageNo = 0;
    Integer pageSize = 1;
    String sortBy = "id";
    Pageable paging = PageRequest.of(pageNo, pageSize, Sort.by(sortBy).descending());

    Slice<Student> pagedResult = repository.findLastStudent(paging);

    return pagedResult.getContent();

Your repository interface should implement the PagingAndSortingRepository


public interface StudentRepository extends JpaRepository<Student,Long>, PagingAndSortingRepository<Student,Long>{

    @Query("select student from Student student")
    Slice<Student> findLastStudent(Pageable paging);

This will add the limit keyword to you query which you can see in the console. Hope this helps.

Method 6

Hardcode the pagination(new PageRequest(0, 1)) to achieve fetch only one record.

    @QueryHints({ @QueryHint(name = "org.hibernate.cacheable", value = "true") })
    @Query("select * from a_table order by a_table_column desc")
    List<String> getStringValue(Pageable pageable);

you have to pass new PageRequest(0, 1)to fetch records and from the list fetch the first record.

Method 7

You can use something like this:

 public interface ICustomerMasterRepository extends CrudRepository<CustomerMaster, String> 
    @Query(value = "SELECT max(c.customer_id) FROM CustomerMaster c ")
    public String getMaxId();

Method 8

The correct way is to write your JPA interface method like this

public interface MyRepository extends PagingAndSortingRepository<EntityClass, KeyClass> {

List<EntityClass> findTop100ByOrderByLastModifiedDesc();

In the method name, “100” denotes how many rows you want which you would have otherwise put in the limit clause. also “LastModified” is the column which you want to sort by.

PagingAndSortingRepository or CrudRepository, both will work for this.

For the sake of completeness, OP’s interface method would be

List<Students> findTop1ByIdDesc();

Method 9

Here a Top Ten Service (it’s a useful example)

(In the Query, I parse the score entity to ScoreTo ( DTO class) by a constructor)

public interface ScoreRepository extends JpaRepository<Scores, UUID> {     
  @Query("SELECT new com.example.parameters.model.to.ScoreTo(u.scoreId , u.level, u.userEmail, u.scoreLearningPoints, u.scoreExperiencePoints, u.scoreCommunityPoints, u.scoreTeamworkPoints, u.scoreCommunicationPoints, u.scoreTotalPoints) FROM Scores u "+
            "order by u.scoreTotalPoints desc")
    List<ScoreTo> findTopScore(Pageable pageable);


public class ScoreService {
    private ScoreRepository scoreRepository;    
    public List<ScoreTo> getTopScores(){
        return scoreRepository.findTopScore(PageRequest.of(0,10));

Method 10

As your query is simple, you can use the solution of the accepted answer, naming your query findFirstByOrderById();

But if your query is more complicated, I also found this way without need to use a native query:

@Query("SELECT MAX(s) FROM Students s ORDER BY s.id DESC")
Students getLastStudentDetails();

Here a practical example where the named query method cannot be used.

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

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