Does R have function startswith or endswith like python?

> startsWith('abc', 'a')
[1] TRUE
> startsWith('abc', 'c')
[1] FALSE

> endsWith('abc', 'a')
[1] FALSE  
> endsWith('abc', 'c')
[1] TRUE

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

As added to base in 3.3.0, startsWith (and endsWith) are exactly this.

> startsWith("what", "wha")
[1] TRUE
> startsWith("what", "ha")
[1] FALSE

https://stat.ethz.ch/R-manual/R-devel/library/base/html/startsWith.html

Method 2

Not inbuilt like that.

Options include grepl and substr.

x <- 'ABCDE'
grepl('^AB', x) # starts with AB?
grepl('DE$', x) # ends with DE?
substr(x, 1, 2) == 'AB'
substr('ABCDE', nchar(x)-1, nchar(x)) == 'DE'

Method 3

The dplyr package’s select statement supports starts_with and ends_with. For example, this selects the columns of the iris data frame that start with Petal

library(dplyr)
select(iris, starts_with("Petal"))

select supports other subcommands too. Try ?select .

Method 4

The simplest way I can think of is to use the %like% operator:

library(data.table)

"foo" %like% "^f"

evaluates as TRUE – Starting with f

"foo" %like% "o$"

evaluates as TRUE – Ending with o

"bar" %like% "a"

evaluates as TRUE – Containing a

Method 5

Borrowing some code from the dplyr package [see this] you could do something like this:

starts_with <- function(vars, match, ignore.case = TRUE) {
  if (ignore.case) match <- tolower(match)
  n <- nchar(match)

  if (ignore.case) vars <- tolower(vars)
  substr(vars, 1, n) == match
}

ends_with <- function(vars, match, ignore.case = TRUE) {
  if (ignore.case) match <- tolower(match)
  n <- nchar(match)

  if (ignore.case) vars <- tolower(vars)
  length <- nchar(vars)

  substr(vars, pmax(1, length - n + 1), length) == match
}

Method 6

This is relatively simple by using the substring function:

> strings = c("abc", "bcd", "def", "ghi", "xyzzd", "a")
> str_to_find = "de"
> substring(strings, 1, nchar(str_to_find)) == str_to_find
[1] FALSE FALSE  TRUE FALSE FALSE FALSE

You cut each string to the desired length with substring. The length being the number of characters you are looking for at the beginning of each string.


All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

0 0 votes
Article Rating
Subscribe
Notify of
guest

0 Comments
Oldest
Newest Most Voted
Inline Feedbacks
View all comments
0
Would love your thoughts, please comment.x
()
x