How to make a set of lists

I have a list of lists like this:

i = [[1, 2, 3], [2, 4, 5], [1, 2, 3], [2, 4, 5]]

I would like to get a list containing “unique” lists (based on their elements) like:

o = [[1, 2, 3], [2, 4, 5]]

I cannot use set() as there are non-hashable elements in the list. Instead, I am doing this:

o = []
for e in i:
  if e not in o:
    o.append(e)

Is there an easier way to do this?

Answers:

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Method 1

You can create a set of tuples, a set of lists will not be possible because of non hashable elements as you mentioned.

>>> l = [[1, 2, 3], [2, 4, 5], [1, 2, 3], [2, 4, 5]]
>>> set(tuple(i) for i in l)
{(1, 2, 3), (2, 4, 5)}

Method 2

i = [[1, 2, 3], [2, 4, 5], [1, 2, 3], [2, 4, 5]]

print([ele for ind, ele in enumerate(i) if ele not in i[:ind]])
[[1, 2, 3], [2, 4, 5]]

If you consider [2, 4, 5] to be equal to [2, 5, 4] then you will need to do further checks

Method 3

You can convert each element to a tuple and then insert it in a set.

Here’s some code with your example:

tmp = set()
a = [[1, 2, 3], [2, 4, 5], [1, 2, 3], [2, 4, 5]]
for i in a:
    tmp.add(tuple(i))

tmp will be like this:

{(1, 2, 3), (2, 4, 5)}

Method 4

Here’s another way to do it:

I = [[1, 2, 3], [2, 4, 5], [1, 2, 3], [2, 4, 5]]
mySet = set()

for j in range(len(I)):
  mySet = mySet | set([tuple(I[j])])

print(mySet)

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0