IOError: [Errno 22] invalid mode (‘r’) or filename: ‘c:\Python27test.txt’

What is wrong with the following:

test_file=open('c:\Python27test.txt','r')

Answers:

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Method 1

t is a tab character. Use a raw string instead:

test_file=open(r'c:Python27test.txt','r')

or double the slashes:

test_file=open('c:\Python27\test.txt','r')

or use forward slashes instead:

test_file=open('c:/Python27/test.txt','r')

Method 2

always use ‘r’ to get a raw string when you want to avoid escape.

test_file=open(r'c:Python27test.txt','r')

Method 3

is an escape character in Python. t gets interpreted as a tab. If you need character in a string, you have to use \.

Your code should be:
test_file=open('c:\Python27\test.txt','r')

Method 4

t in a string marks an escape sequence for a tab character. For a literal , use \.

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0