Does it call forward() in nn.Module? I thought when we call the model, forward method is being used.
Why do we need to specify train()?
Answers:
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Method 1
model.train() tells your model that you are training the model. This helps inform layers such as Dropout and BatchNorm, which are designed to behave differently during training and evaluation. For instance, in training mode, BatchNorm updates a moving average on each new batch; whereas, for evaluation mode, these updates are frozen.
More details:
model.train() sets the mode to train
(see source code). You can call either model.eval() or model.train(mode=False) to tell that you are testing.
It is somewhat intuitive to expect train function to train model but it does not do that. It just sets the mode.
Method 2
Here is the code for nn.Module.train():
def train(self, mode=True):
r"""Sets the module in training mode."""
self.training = mode
for module in self.children():
module.train(mode)
return self
Here is the code for nn.Module.eval():
def eval(self):
r"""Sets the module in evaluation mode."""
return self.train(False)
By default, the self.training flag is set to True, i.e., modules are in train mode by default. When self.training is False, the module is in the opposite state, eval mode.
Of the most commonly used layers, only Dropout and BatchNorm care about that flag.
Method 3
model.train() |
model.eval() |
|---|---|
| Sets model in training mode i.e. • BatchNorm layers use per-batch statistics • Dropout layers activated etc
|
Sets model in evaluation (inference) mode i.e.
• |
Equivalent to model.train(False). |
Note: neither of these function calls run forward / backward passes. They tell the model how to act when run.
This is important as some modules (layers) (e.g. Dropout, BatchNorm) are designed to behave differently during training vs inference, and hence the model will produce unexpected results if run in the wrong mode.
Method 4
There are two ways of letting the model know your intention i.e do you want to train the model or do you want to use the model to evaluate.
In case of model.train() the model knows it has to learn the layers and when we use model.eval() it indicates the model that nothing new is to be learnt and the model is used for testing.
model.eval() is also necessary because in pytorch if we are using batchnorm and during test if we want to just pass a single image, pytorch throws an error if model.eval() is not specified.
Method 5
Consider the following model
import torch
import torch.nn.functional as F
from torch_geometric.nn import GCNConv
class GraphNet(torch.nn.Module):
def __init__(self, num_node_features, num_classes):
super(GraphNet, self).__init__()
self.conv1 = GCNConv(num_node_features, 16)
self.conv2 = GCNConv(16, num_classes)
def forward(self, data):
x, edge_index = data.x, data.edge_index
x = self.conv1(x, edge_index)
x = F.dropout(x, training=self.training) #Look here
x = self.conv2(x, edge_index)
return F.log_softmax(x, dim=1)
Here, the functioning of dropout differ in different modes of operation. As you can see, it works only when self.training==True. So, when you type model.train(), the model’s forward function will perform dropout otherwise it will not (say when model.eval() or model.train(mode=False)).
Method 6
The current official documentation states the following:
This has any [sic] effect only on certain modules. See documentations of particular modules for details of their behaviors in training/evaluation mode, if they are affected, e.g. Dropout, BatchNorm, etc.
All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0