Clicking on svg using selenium python

svg icon is clickable.

<div class="some-class">
    <svg aria-label="Search" class="some-icon" width="24" height="24" fill="#000" viewBox="0 0 24 24">
        <path d="M9.5,...,5 9.5,5Z">
        </path>
    </svg>
</div>

Sample code:

from selenium import webdriver

driver = webdriver.Chrome(CHROME_DRIVER_LOCATION)
driver.find_element_by_xpath('//*[@id="SearchForm"]/div[1]/span/div[1]/div[2]/svg/path').click()

Error:

no such element: Unable to locate element: {“method”:”xpath”,”selector”:”//*[@id=”SearchForm”]/div[1]/span/div[1]/div[2]/svg/path”}

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Answers:

Method 1

Method 2

Method 3

Answers:

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Method 1

To click() on the svg icon you can use the following solution:

driver.find_element_by_xpath('//div[@class="some-class"]/*[name()="svg"][@aria-label="Search"]').click()

You can find a couple of relevant discussions in:

Method 2

The “svg” elements are not from the XHTML namespace but belongs to SVG namespace. Hence you have to specify name()=”svg” while constructing the xpath for svg tags.
for example :
“/*[name()=’svg’]/*[name()=’path’] “

For your reference , please find below discussion
How to click on SVG elements using XPath and Selenium WebDriver through Java

Method 3

For my case the following worked:

driver.find_element_by_xpath('//div[@class="some-class"]/*[name()="svg"][@aria-label="Search"]').click()

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

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