How do I convert a datetime to date?

How do I convert a datetime.datetime object (e.g., the return value of datetime.datetime.now()) to a datetime.date object in Python?

Answers:

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Method 1

Use the date() method:

datetime.datetime.now().date()

Method 2

From the documentation:

datetime.datetime.date()

Return date object with same year, month and day.

Method 3

You use the datetime.datetime.date() method:

datetime.datetime.now().date()

Obviously, the expression above can (and should IMHO 🙂 be written as:

datetime.date.today()

Method 4

You can convert a datetime object to a date with the date() method of the date time object, as follows:

<datetime_object>.date()

Method 5

Answer updated to Python 3.7 and more

Here is how you can turn a date-and-time object

(aka datetime.datetime object, the one that is stored inside models.DateTimeField django model field)

into a date object (aka datetime.date object):

from datetime import datetime

#your date-and-time object
# let's supposed it is defined as
datetime_element = datetime(2020, 7, 10, 12, 56, 54, 324893)

# where
# datetime_element = datetime(year, month, day, hour, minute, second, milliseconds)

# WHAT YOU WANT: your date-only object
date_element = datetime_element.date()

And just to be clear, if you print those elements, here is the output :

print(datetime_element)

2020-07-10 12:56:54.324893

print(date_element)

2020-07-10

Method 6

you could enter this code form for (today date & Names of the Day & hour) :
datetime.datetime.now().strftime('%y-%m-%d %a %H:%M:%S')

’19-09-09 Mon 17:37:56′

and enter this code for (today date simply):
datetime.date.today().strftime('%y-%m-%d')

’19-09-10′

for object :
datetime.datetime.now().date()
datetime.datetime.today().date()
datetime.datetime.utcnow().date()
datetime.datetime.today().time()
datetime.datetime.utcnow().date()
datetime.datetime.utcnow().time()

Method 7

import time
import datetime

# use mktime to step by one day
# end - the last day, numdays - count of days to step back
def gen_dates_list(end, numdays):
  start = end - datetime.timedelta(days=numdays+1)
  end   = int(time.mktime(end.timetuple()))
  start = int(time.mktime(start.timetuple()))
  # 86400 s = 1 day
  return xrange(start, end, 86400)

# if you need reverse the list of dates
for dt in reversed(gen_dates_list(datetime.datetime.today(), 100)):
    print datetime.datetime.fromtimestamp(dt).date()

Method 8

Solved: AttributeError: 'Series' object has no attribute 'date'

You can use as below,

df["date"] = pd.to_datetime(df["date"]).dt.date

where in above code date contains both date and time (2020-09-21 22:32:00), using above code we can get only date as (2020-09-21)

Method 9

I use data.strftime('%y-%m-%d') with lambda to transfer column to date

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0