Making a string out of a string and an integer in Python

I get this error when trying to take an integer and prepend “b” to it, converting it into a string:

  File "program.py", line 19, in getname
    name = "b" + num
TypeError: Can't convert 'int' object to str implicitly

That’s related to this function:

num = random.randint(1,25)
name = "b" + num

Answers:

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Method 1

name = 'b' + str(num)

or

name = 'b%s' % num

as S.Lott notes, the mingle operator ‘%’ is deprecated for Python 3 and up. And I stole the name “mingle” from INTERCAL but that’s how I talk about it and wanted to see it in print at least once before – like the dodo – it vanishes from the face of the earth.

Method 2

Python won’t automatically convert types in the way that languages such as JavaScript or PHP do.

You have to convert it to a string, or use a formatting method.

name="b"+str(num)

or printf style formatting (this has been deprecated in python3)

name="b%s" % (num,)

or the new .format string method

name="b{0}".format(num)

Method 3

Python 3.6 has f-strings where you can directly put the variable names without the need to use format:

>>> num=12
>>> f"b{num}"
'b12'

Method 4

Yeah, python doesn’t having implicit int to string conversions.

try str(num) instead

Method 5

name = "b{0:d}".format( num )

Method 6

Correct answers have already been given but I want to chime in and say that you should always use str(var) every time you intend to use var as a string, regardless of whether you know it is a string or not.

Better safe than sorry.

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0