I was looking for a way to annotate my bars in a Pandas bar plot with the rounded numerical values from my DataFrame.
>>> df=pd.DataFrame({'A':np.random.rand(2),'B':np.random.rand(2)},index=['value1','value2'] )
>>> df
A B
value1 0.440922 0.911800
value2 0.588242 0.797366
I would like to get something like this:

I tried with this code sample, but the annotations are all centered on the x ticks:
>>> ax = df.plot(kind='bar')
>>> for idx, label in enumerate(list(df.index)):
for acc in df.columns:
value = np.round(df.ix[idx][acc],decimals=2)
ax.annotate(value,
(idx, value),
xytext=(0, 15),
textcoords='offset points')
Answers:
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Method 1
You get it directly from the axes’ patches:
for p in ax.patches:
ax.annotate(str(p.get_height()), (p.get_x() * 1.005, p.get_height() * 1.005))
You’ll want to tweak the string formatting and the offsets to get things centered, maybe use the width from p.get_width(), but that should get you started. It may not work with stacked bar plots unless you track the offsets somewhere.
Method 2
As of matplotlib 3.4.0:
A new
Axes.bar_labelhelper method has been added for auto-labeling bar charts.
For single-group bar charts, supply ax.containers[0]:
df = pd.DataFrame({'A': np.random.rand(2)}, index=['value1', 'value2'])
ax = df.plot.barh()
ax.bar_label(ax.containers[0])
For multi-group bar charts, iterate ax.containers:
df = pd.DataFrame({'A': np.random.rand(2), 'B': np.random.rand(2)}, index=['value1', 'value2'])
ax = df.plot.bar()
for container in ax.containers:
ax.bar_label(container)
See matplotlib’s bar label demos for comprehensive examples using the optional styling params:
Axes.bar_label(self, container, labels=None, *, fmt='%g', label_type='edge', padding=0, **kwargs)
Method 3
Solution which also handles the negative values with sample float formatting.
Still needs tweaking offsets.
df=pd.DataFrame({'A':np.random.rand(2)-1,'B':np.random.rand(2)},index=['val1','val2'] )
ax = df.plot(kind='bar', color=['r','b'])
x_offset = -0.03
y_offset = 0.02
for p in ax.patches:
b = p.get_bbox()
val = "{:+.2f}".format(b.y1 + b.y0)
ax.annotate(val, ((b.x0 + b.x1)/2 + x_offset, b.y1 + y_offset))
Method 4
The ax gives us the size of the box.
x_position=##define a value
y_position=##define a value
for patch in ax.patches:
b= patch.get_bbox()
y_value=b.y1-b.y0
ax.annotate(y_value, "x_position" , "y_position"))
plt.show()
for more clarity::
Bbox(x0=3.75, y0=0.0, x1=4.25, y1=868.0)
Bbox(x0=4.75, y0=0.0, x1=5.25, y1=868.0)
Bbox(x0=5.75, y0=0.0, x1=6.25, y1=1092.0)
Bbox(x0=6.75, y0=0.0, x1=7.25, y1=756.0)
Bbox(x0=7.75, y0=0.0, x1=8.25, y1=756.0)
Bbox(x0=8.75, y0=0.0, x1=9.25, y1=588.0)
Bbox(x0=3.75, y0=868.0, x1=4.25, y1=3724.0)
Bbox(x0=4.75, y0=868.0, x1=5.25, y1=3528.0)
Bbox(x0=5.75, y0=1092.0, x1=6.25, y1=3948.0)
Bbox(x0=6.75, y0=756.0, x1=7.25, y1=2884.0)
Bbox(x0=7.75, y0=756.0, x1=8.25, y1=3024.0)
Bbox(x0=0.75, y0=4004.0, x1=1.25, y1=4396.0)
Bbox(x0=1.75, y0=3668.0, x1=2.25, y1=4060.0)
Bbox(x0=2.75, y0=3864.0, x1=3.25, y1=4060.0)
this is the output of patch.get_bbox() in my program.
we can extract the bounding box details from here and manipulate for our requirement
All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

