Access a control inside a the LayoutTemplate of a ListView

How do I access a Control in the LayoutTemplate of a ListView control?

I need to get to litControlTitle and set its Text attribute.

<asp:ListView ID="lv" runat="server">
  <LayoutTemplate>
    <asp:Literal ID="litControlTitle" runat="server" />
    <asp:PlaceHolder ID="itemPlaceHolder" runat="server" />
  </LayoutTemplate>
  <ItemTemplate>
  </ItemTemplate>
</asp:ListView>

Any thoughts? Perhaps via the OnLayoutCreated event?

Answers:

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Method 1

Try this:

((Literal)lv.FindControl("litControlTitle")).Text = "Your text";

Method 2

The complete solution:

<asp:ListView ID="lv" OnLayoutCreated="OnLayoutCreated" runat="server">
  <LayoutTemplate>
    <asp:Literal ID="lt_Title" runat="server" />
    <asp:PlaceHolder ID="itemPlaceHolder" runat="server" />
  </LayoutTemplate>
  <ItemTemplate>
  </ItemTemplate>
</asp:ListView>

In codebehind:

protected void OnLayoutCreated(object sender, EventArgs e)
{
    (lv.FindControl("lt_Title") as Literal).Text = "Your text";
}

Method 3

This technique works for template layout; use the init event of the control:

<asp:ListView ID="lv" runat="server" OnDataBound="lv_DataBound">
  <LayoutTemplate>
    <asp:Literal ID="litControlTitle" runat="server" OnInit="litControlTitle_Init" />
    <asp:PlaceHolder ID="itemPlaceHolder" runat="server" />
  </LayoutTemplate>
  <ItemTemplate>
  </ItemTemplate>
</asp:ListView>

And capture a reference to the control for use in the code-behind (e.g) in the ListView’s DataBound event:

private Literal litControlTitle;

protected void litControlTitle_Init(object sender, EventArgs e)
{
    litControlTitle = (Literal) sender;
}

protected void lv_DataBound(object sender, EventArgs e)
{
    litControlTitle.Text = "Title...";
}

Method 4

For Nested LV Loop:

void lvSecondLevel_LayoutCreated(object sender, EventArgs e)
{
    Literal litText = lvFirstLevel.FindControl("lvSecondLevel").FindControl("litText") as Literal;
    litMainMenuText.Text = "This is test";
}

Method 5

In case you need the VB version, here it is

Dim litControl = CType(lv.FindControl("litControlTitle"), Literal)
litControl.Text = "your text"

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0