Apply function to each cell in DataFrame

I have a dataframe that may look like this:

A        B        C
foo      bar      foo bar
bar foo  foo      bar

I want to look through every element of each row (or every element of each column) and apply the following function to get the subsequent DF:

def foo_bar(x):
    return x.replace('foo', 'wow')

A        B        C
wow      bar      wow bar
bar wow  wow      bar

Is there a simple one-liner that can apply a function to each cell?

This is a simplistic example so there may be an easier way to execute this specific example other than applying a function, but what I am really asking about is how to apply a function in every cell within a dataframe.

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

You can use applymap() which is concise for your case.

df.applymap(foo_bar)

#     A       B       C
#0  wow     bar wow bar
#1  bar wow wow     bar

Another option is to vectorize your function and then use apply method:

import numpy as np
df.apply(np.vectorize(foo_bar))
#     A       B       C
#0  wow     bar wow bar
#1  bar wow wow     bar

Method 2

I guess you could use np.vectorize:

>>> df[:] = np.vectorize(foo_bar)(df)
>>> df
       A    B    C
foo  bar  wow  bar
bar  wow  wow  bar
>>>

This might be quicker, since it’s using numpy.


All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

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