change forecolor af a special word in gridview cell

I want to change the color of some special words NOT all words in a gridview cell.
Here is the code:

protected void gvContents_RowDataBound(object sender, GridViewRowEventArgs e)
{
    if (e.Row.RowType == DataControlRowType.DataRow)
    {
        if (e.Row.Cells[3].Text.Contains("Special"))
        {
            //set The "Special" word only forecolor to red
        }
        else if (e.Row.Cells[3].Text == "Perishable")
        {
            //set The "Perishable" word only forecolor to blue
        }
        else if (e.Row.Cells[3].Text == "Danger")
        {
            //set The "Danger" word only forecolor to yellow
        }
    }
}

and the cell text might be like here: Radioactive : Danger or this: Human Body : Special ,Perishable. What should I do?

Answers:

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Method 1

Use a combination of span tags and CSS classes. First create the CSS classes in your aspx code:

<style>
    .redWord
    {
        color: Red;
    }
    .blueWord
    {
        color: Blue;
    }
    .yellowWord
    {
        color: Yellow;
    }
</style>

then replace all occurences of Special to <span class='redWord'>Special</span>, Perishable to <span class='blueWord'>Perishable</span>, and Danger to <span class='yellowWord'>Danger</span>:

protected void gvContents_RowDataBound(object sender, GridViewRowEventArgs e)
{
    if (e.Row.RowType == DataControlRowType.DataRow)
    {
        e.Row.Cells[3].Text = e.Row.Cells[3].Text.Replace("Special", "<span class='redWord'>Special</span>")
                              .Replace("Perishable", "<span class='blueWord'>Perishable</span>")
                              .Replace("Danger", "<span class='yellowWord'>Danger</span>");
    }
}

Method 2

In the CellFormatting event handler, add the below code

void dataGridView1_CellFormatting(object sender, DataGridViewCellFormattingEventArgs e)
    {
        if (e.Value != null && e.Value.ToString() == "Special")
        {
            e.CellStyle.ForeColor = Color.Red;
        }
    }

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0