I need to implement scikit-learn’s kMeans for clustering text documents. The example code works fine as it is but takes some 20newsgroups data as input. I want to use the same code for clustering a list of documents as shown below:
documents = ["Human machine interface for lab abc computer applications",
"A survey of user opinion of computer system response time",
"The EPS user interface management system",
"System and human system engineering testing of EPS",
"Relation of user perceived response time to error measurement",
"The generation of random binary unordered trees",
"The intersection graph of paths in trees",
"Graph minors IV Widths of trees and well quasi ordering",
"Graph minors A survey"]
What changes do i need to do in kMeans example code to use this list as input? (Simply taking ‘dataset = documents’ doesn’t work)
Answers:
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Method 1
This is a simpler example:
from sklearn.feature_extraction.text import TfidfVectorizer
from sklearn.cluster import KMeans
from sklearn.metrics import adjusted_rand_score
documents = ["Human machine interface for lab abc computer applications",
"A survey of user opinion of computer system response time",
"The EPS user interface management system",
"System and human system engineering testing of EPS",
"Relation of user perceived response time to error measurement",
"The generation of random binary unordered trees",
"The intersection graph of paths in trees",
"Graph minors IV Widths of trees and well quasi ordering",
"Graph minors A survey"]
vectorize the text i.e. convert the strings to numeric features
vectorizer = TfidfVectorizer(stop_words='english') X = vectorizer.fit_transform(documents)
cluster documents
true_k = 2 model = KMeans(n_clusters=true_k, init='k-means++', max_iter=100, n_init=1) model.fit(X)
print top terms per cluster clusters
print("Top terms per cluster:")
order_centroids = model.cluster_centers_.argsort()[:, ::-1]
terms = vectorizer.get_feature_names()
for i in range(true_k):
print "Cluster %d:" % i,
for ind in order_centroids[i, :10]:
print ' %s' % terms[ind],
print
If you want to have a more visual idea of how this looks like see this answer.
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