I am writing a program that stores data in a dictionary object, but this data needs to be saved at some point during the program execution and loaded back into the dictionary object when the program is run again.
How would I convert a dictionary object into a string that can be written to a file and loaded back into a dictionary object? This will hopefully support dictionaries containing dictionaries.
Answers:
Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.
Method 1
The json module is a good solution here. It has the advantages over pickle that it only produces plain text output, and is cross-platform and cross-version.
import json json.dumps(dict)
Method 2
If your dictionary isn’t too big maybe str + eval can do the work:
dict1 = {'one':1, 'two':2, 'three': {'three.1': 3.1, 'three.2': 3.2 }}
str1 = str(dict1)
dict2 = eval(str1)
print(dict1 == dict2)
You can use ast.literal_eval instead of eval for additional security if the source is untrusted.
Method 3
I use json:
import json
# convert to string
input = json.dumps({'id': id })
# load to dict
my_dict = json.loads(input)
Method 4
Why not to use Python 3’s inbuilt ast library’s function literal_eval. It is better to use literal_eval instead of eval
import ast
str_of_dict = "{'key1': 'key1value', 'key2': 'key2value'}"
ast.literal_eval(str_of_dict)
will give output as actual Dictionary
{'key1': 'key1value', 'key2': 'key2value'}
And If you are asking to convert a Dictionary to a String then, How about using str() method of Python.
Suppose the dictionary is :
my_dict = {'key1': 'key1value', 'key2': 'key2value'}
And this will be done like this :
str(my_dict)
Will Print :
"{'key1': 'key1value', 'key2': 'key2value'}"
This is the easy as you like.
Method 5
Use the pickle module to save it to disk and load later on.
Method 6
Convert dictionary into JSON (string)
import json
mydict = { "name" : "Don",
"surname" : "Mandol",
"age" : 43}
result = json.dumps(mydict)
print(result[0:20])
will get you:
{“name”: “Don”, “sur
Convert string into dictionary
back_to_mydict = json.loads(result)
Method 7
In Chinese language you should do the following adjustments:
import codecs
fout = codecs.open("xxx.json", "w", "utf-8")
dict_to_json = json.dumps({'text':"中文"},ensure_ascii=False,indent=2)
fout.write(dict_to_json + 'n')
Method 8
I think you should consider using the shelve module which provides persistent file-backed dictionary-like objects. It’s easy to use in place of a “real” dictionary because it almost transparently provides your program with something that can be used just like a dictionary, without the need to explicitly convert it to a string and then write to a file (or vice-versa).
The main difference is needing to initially open() it before first use and then close() it when you’re done (and possibly sync()ing it, depending on the writeback option being used). Any “shelf” file objects create can contain regular dictionaries as values, allowing them to be logically nested.
Here’s a trivial example:
import shelve
shelf = shelve.open('mydata') # open for reading and writing, creating if nec
shelf.update({'one':1, 'two':2, 'three': {'three.1': 3.1, 'three.2': 3.2 }})
shelf.close()
shelf = shelve.open('mydata')
print shelf
shelf.close()
Output:
{'three': {'three.1': 3.1, 'three.2': 3.2}, 'two': 2, 'one': 1}
Method 9
You may find the json.dumps() method needs help handling some object types.
Credit goes to the top answer of this post for the following:
import json json.dumps(my_dictionary, indent=4, sort_keys=True, default=str)
Method 10
If you care about the speed use ujson (UltraJSON), which has the same API as json:
import ujson
ujson.dumps([{"key": "value"}, 81, True])
# '[{"key":"value"},81,true]'
ujson.loads("""[{"key": "value"}, 81, true]""")
# [{u'key': u'value'}, 81, True]
Method 11
I use yaml for that if needs to be readable (neither JSON nor XML are that IMHO), or if reading is not necessary I use pickle.
Write
from pickle import dumps, loads
x = dict(a=1, b=2)
y = dict(c = x, z=3)
res = dumps(y)
open('/var/tmp/dump.txt', 'w').write(res)
Read back
from pickle import dumps, loads
rev = loads(open('/var/tmp/dump.txt').read())
print rev
Method 12
I figured out the problem was not with my dict object it was the keys and values that were of RubyString type after loading it with RubyMarshl ‘loads’ method
So i did this:
dic_items = dict.items()
new_dict = {str(key): str(value) for key, value in dic_items}
All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0