Counting each letter’s frequency in a string

This is a question from pyschools.

I did get it right, but I’m guessing that there would be a simpler method. Is this the simplest way to do this?

def countLetters(word):
    letterdict={}
    for letter in word:
        letterdict[letter] = 0
    for letter in word:
        letterdict[letter] += 1
    return letterdict

This should look something like this:

>>> countLetters('google')
{'e': 1, 'g': 2, 'l': 1, 'o': 2}

Answers:

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Method 1

In 2.7+:

import collections
letters = collections.Counter('google')

Earlier (2.5+, that’s ancient by now):

import collections
letters = collections.defaultdict(int)
for letter in word:
    letters[letter] += 1

Method 2

>>> import collections
>>> print collections.Counter("google")
Counter({'o': 2, 'g': 2, 'e': 1, 'l': 1})

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0