Deleting list elements based on condition

I have a list of lists: [word, good freq, bad freq, change_status]

list_1 = [['good',100, 20, 0.2],['bad', 10, 0, 0.0],['change', 1, 2, 2]]

I would like to delete from the list all elements which don’t satisfy a condition.

So if change_status > 0.3 and bad_freq < 5 then I would like to delete that the elements corresponding to it.

So the list_1 would be modified as,

list_1 = [['good',100, 20, 0.2],['bad', 10, 0, 0.0]]

How do I selective do that?

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

list_1 = [['good',100, 20, 0.2],['bad', 10, 0, 0.0],['change', 1, 2, 2]]
list_1 = [item for item in list_1 if item[2] >= 5 or item[3] >= 0.3]

You can also use if not (item[2] < 5 and item[3] < 0.3) for the condition if you want.

Method 2

Use the filter function with an appropriate function.

list_1 = filter(lambda x: x[3] <= 0.3 and x[2] < 5, list_1)

Demo:

In [1]: list_1 = [['good',100, 20, 0.2],['bad', 10, 0, 0.0],['change', 1, 2, 2]]
In [2]: filter(lambda x: x[3] <= 0.3 and x[2] < 5, list_1)
Out[2]: [['bad', 10, 0, 0.0]]

Note that good doesn’t satisfy your condition (20 < 5 is false) even though you said so in your question!


If you have many elements you might want to use the equivalent function from itertools:

from itertools import ifilter
filtered = ifilter(lambda x: x[3] <= 0.3 and x[2] < 5, list_1)


All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

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