Formatting floats in a numpy array

If I have a numpy array like this:

[2.15295647e+01, 8.12531501e+00, 3.97113829e+00, 1.00777250e+01]

how can I move the decimal point and format the numbers so I end up with a numpy array like this:

[21.53, 8.13, 3.97, 10.08]

np.around(a, decimals=2) only gives me [2.15300000e+01, 8.13000000e+00, 3.97000000e+00, 1.00800000e+01] Which I don’t want and I haven’t found another way to do it.

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

In order to make numpy display float arrays in an arbitrary format, you can define a custom function that takes a float value as its input and returns a formatted string:

In [1]: float_formatter = "{:.2f}".format

The f here means fixed-point format (not ‘scientific’), and the .2 means two decimal places (you can read more about string formatting here).

Let’s test it out with a float value:

In [2]: float_formatter(1.234567E3)
Out[2]: '1234.57'

To make numpy print all float arrays this way, you can pass the formatter= argument to np.set_printoptions:

In [3]: np.set_printoptions(formatter={'float_kind':float_formatter})

Now numpy will print all float arrays this way:

In [4]: np.random.randn(5) * 10
Out[4]: array([5.25, 3.91, 0.04, -1.53, 6.68]

Note that this only affects numpy arrays, not scalars:

In [5]: np.pi
Out[5]: 3.141592653589793

It also won’t affect non-floats, complex floats etc – you will need to define separate formatters for other scalar types.

You should also be aware that this only affects how numpy displays float values – the actual values that will be used in computations will retain their original precision.

For example:

In [6]: a = np.array([1E-9])

In [7]: a
Out[7]: array([0.00])

In [8]: a == 0
Out[8]: array([False], dtype=bool)

numpy prints a as if it were equal to 0, but it is not – it still equals 1E-9.

If you actually want to round the values in your array in a way that affects how they will be used in calculations, you should use np.round, as others have already pointed out.

Method 2

You can use round function. Here some example

numpy.round([2.15295647e+01, 8.12531501e+00, 3.97113829e+00, 1.00777250e+01],2)
array([ 21.53,   8.13,   3.97,  10.08])

IF you want change just display representation, I would not recommended to alter printing format globally, as it suggested above. I would format my output in place.

>>a=np.array([2.15295647e+01, 8.12531501e+00, 3.97113829e+00, 1.00777250e+01])
>>> print([ "{:0.2f}".format(x) for x in a ])
['21.53', '8.13', '3.97', '10.08']

Method 3

You’re confusing actual precision and display precision. Decimal rounding cannot be represented exactly in binary. You should try:

> np.set_printoptions(precision=2)
> np.array([5.333333])
array([ 5.33])

Method 4

[ round(x,2) for x in [2.15295647e+01, 8.12531501e+00, 3.97113829e+00, 1.00777250e+01]]


All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

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