Get all child elements

In Selenium with Python is it possible to get all the children of a WebElement as a list?

Answers:

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Method 1

Yes, you can achieve it by find_elements_by_css_selector("*") or find_elements_by_xpath(".//*").

However, this doesn’t sound like a valid use case to find all children of an element. It is an expensive operation to get all direct/indirect children. Please further explain what you are trying to do. There should be a better way.

from selenium import webdriver

driver = webdriver.Firefox()
driver.get("http://www.stackoverflow.com")

header = driver.find_element_by_id("header")

# start from your target element, here for example, "header"
all_children_by_css = header.find_elements_by_css_selector("*")
all_children_by_xpath = header.find_elements_by_xpath(".//*")

print 'len(all_children_by_css): ' + str(len(all_children_by_css))
print 'len(all_children_by_xpath): ' + str(len(all_children_by_xpath))

Method 2

Yes, you can use find_elements_by_ to retrieve children elements into a list. See the python bindings here: http://selenium-python.readthedocs.io/locating-elements.html

Example HTML:

<ul class="bar">
    <li>one</li>
    <li>two</li>
    <li>three</li>
</ul>

You can use the find_elements_by_ like so:

parentElement = driver.find_element_by_class_name("bar")
elementList = parentElement.find_elements_by_tag_name("li")

If you want help with a specific case, you can edit your post with the HTML you’re looking to get parent and children elements from.

Method 3

Another veneration of find_elements_by_xpath(".//*") is:

from selenium.webdriver.common.by import By


find_elements(By.XPATH, ".//*")

Method 4

You can’t use

all_children_by_css = header.find_elements_by_css_selector("*")

You now need to use

all_children_by_css = header.find_elements(By.XPATH, "*')

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0