How to convert a file into a dictionary?

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Method 1

d = {}
with open("file.txt") as f:
    for line in f:
       (key, val) = line.split()
       d[int(key)] = val

Method 2

This will leave the key as a string:

with open('infile.txt') as f:
  d = dict(x.rstrip().split(None, 1) for x in f)

Method 3

You can also use a dict comprehension like:

with open("infile.txt") as f:
    d = {int(k): v for line in f for (k, v) in [line.strip().split(None, 1)]}

Method 4

def get_pair(line):
    key, sep, value = line.strip().partition(" ")
    return int(key), value

with open("file.txt") as fd:    
    d = dict(get_pair(line) for line in fd)

Method 5

By dictionary comprehension

d = { line.split()[0] : line.split()[1] for line in open("file.txt") }

Or By pandas

import pandas as pd 
d = pd.read_csv("file.txt", delimiter=" ", header = None).to_dict()[0]

Method 6

Simple Option

Most methods for storing a dictionary use JSON, Pickle, or line reading. Providing you’re not editing the dictionary outside of Python, this simple method should suffice for even complex dictionaries. Although Pickle will be better for larger dictionaries.

x = {1:'a', 2:'b', 3:'c'}
f = 'file.txt'
print(x, file=open(f,'w'))    # file.txt >>> {1:'a', 2:'b', 3:'c'}
y = eval(open(f,'r').read())
print(x==y)                   # >>> True

Method 7

If you love one liners, try:

d=eval('{'+re.sub(''[s]*?'','':'',re.sub(r'([^'+input('SEP: ')+',]+)','''+r'1'+''',open(input('FILE: ')).read().rstrip('n').replace('n',',')))+'}')

Input FILE = Path to file, SEP = Key-Value separator character

Not the most elegant or efficient way of doing it, but quite interesting nonetheless 🙂

Method 8

IMHO a bit more pythonic to use generators (probably you need 2.7+ for this):

with open('infile.txt') as fd:
    pairs = (line.split(None) for line in fd)
    res   = {int(pair[0]):pair[1] for pair in pairs if len(pair) == 2 and pair[0].isdigit()}

This will also filter out lines not starting with an integer or not containing exactly two items

Method 9

I had a requirement to take values from text file and use as key value pair. i have content in text file as key = value, so i have used split method with separator as “=” and
wrote below code

d = {}
file = open("filename.txt")
for x in file:
    f = x.split("=")
    d.update({f[0].strip(): f[1].strip()})

By using strip method any spaces before or after the “=” separator are removed and you will have the expected data in dictionary format

Method 10

import re

my_file = open('file.txt','r')
d = {}
for i in my_file:
  g = re.search(r'(d+)s+(.*)', i) # glob line containing an int and a string
  d[int(g.group(1))] = g.group(2)

Method 11

Here’s another option…

events = {}
for line in csv.reader(open(os.path.join(path, 'events.txt'), "rb")):
    if line[0][0] == "#":
        continue
    events[line[0]] = line[1] if len(line) == 2 else line[1:]

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

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