How to convert date to word format?

I have one date like 12/05/2012 now i would like to change that format in to simple string.

for ex.

string newdate = new string();
newdate = "12/05/2012";
DateTime Bdate = DateTime.ParseExact(Newdate, "dd/MM/yyyy", System.Globalization.CultureInfo.InvariantCulture);

now my BDate is DateTime
ie. BDate= 2012/05/12

now i want to do something like

if my Bdate is 12/05/2012
so i want a string which is similar like “Twelve May two thousand twelve”

How can i do this?

Please help me…

Thanks in advance….

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

You’ll need to look at each date part and use a function to get the written equivalent. I’ve included a class below that converts integers to written text, and extended it to support DateTime conversion as well:

public static class WrittenNumerics
{
    static readonly string[] ones = new string[] { "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" };
    static readonly string[] teens = new string[] { "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };
    static readonly string[] tens = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
    static readonly string[] thousandsGroups = { "", " Thousand", " Million", " Billion" };

    private static string FriendlyInteger(int n, string leftDigits, int thousands)
    {
        if (n == 0)
            return leftDigits;

        string friendlyInt = leftDigits;
        if (friendlyInt.Length > 0)
            friendlyInt += " ";

        if (n < 10)
            friendlyInt += ones[n];
        else if (n < 20)
            friendlyInt += teens[n - 10];
        else if (n < 100)
            friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
        else if (n < 1000)
            friendlyInt += FriendlyInteger(n % 100, (ones[n / 100] + " Hundred"), 0);
        else
            friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands + 1), 0);

        return friendlyInt + thousandsGroups[thousands];
    }

    public static string DateToWritten(DateTime date)
    {
        return string.Format("{0} {1} {2}", IntegerToWritten(date.Day), date.ToString("MMMM"), IntegerToWritten(date.Year));
    }

    public static string IntegerToWritten(int n)
    {
        if (n == 0)
            return "Zero";
        else if (n < 0)
            return "Negative " + IntegerToWritten(-n);

        return FriendlyInteger(n, "", 0);
    }
}

_{Disclaimer: Basic functionality courtesy of @Wedge}

Using this class, just call the DateToWritten method:

var output = WrittenNumerics.DateToWritten(DateTime.Today);

The output of the above is: Twelve May Two Thousand Twelve

Method 2

This isn’t what you want, but the closest I can suggest using built-in functionality is ToLongDateString, which gives you the name of the month and is obviously culture-sensitive.

string str = bdate.ToLongDateString();
// Assuming en-US culture, this would give: "Saturday, May 12, 2012"

Method 3

Suppose 12/05/2012 is a string, then you have to tokenize it into elements which separated by slash “/”. E.g:

“12/05/2012” -> [“12”, “05”, “2012”]

Next, you define yourself a rule which parses these elements to what you expect. Say, “12” is “twelve”, “05” is “five” or “May”, etc.

Method 4

string MyDate = "12/05/2012";
DateTime expected = Convert.ToDateTime(MyDate);
string MyNewDate = expected.ToString("dd MMM yyyy");

Check other date format on this site https://www.mikesdotnetting.com/article/23/date-formatting-in-c .

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0