How to pass list elements as arguments

I want to pass elements of list as function arguments like this:

def foo(a, b, c):
    # do something

list = [1, 2, 3]
foo(list)

I can’t use foo(list[0], list[1], list[2]), because I don’t know how many elements the list has and how many arguments the function takes.

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Answers:

Method 1

Answers:

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Method 1

Use the * argument unpacking operator:

seq = [1, 2, 3]
foo(*seq)

So in the input function you could use

getattr(self, func)(*args)

PS. Don’t name your variables list, since it shadows the built-in of the same name.

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

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