I am using python 2.7 requests module to download a binary file using the following code, how to make this code “auto-resume” the download from partially downloaded file.
r = requests.get(self.fileurl, stream=True, verify=False, allow_redirects=True)
if r.status_code == 200:
CHUNK_SIZE = 8192
bytes_read = 0
with open(FileSave, 'wb') as f:
itrcount=1
for chunk in r.iter_content(CHUNK_SIZE):
itrcount=itrcount+1
f.write(chunk)
bytes_read += len(chunk)
total_per = 100 * float(bytes_read)/float(long(audioSize)+long(videoSize))
self.progress_updates.emit('%dn%s' % (total_per, 'Download Progress : ' + self.size_human(itrcount*CHUNK_SIZE) + '/' + Total_Size))
r.close()
I would prefer to use only requests module to achieve this if possible.
Answers:
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Method 1
If the web server supports the range request then you can add the Range header to your request:
Range: bytes=StartPos-StopPos
You will receive the part between StartPos and StopPos. If dont know the StopPos just use:
Range: bytes=StartPos-
So your code would be:
def resume_download(fileurl, resume_byte_pos):
resume_header = {'Range': 'bytes=%d-' % resume_byte_pos}
return requests.get(fileurl, headers=resume_header, stream=True, verify=False, allow_redirects=True)
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