Given the following data frame:
import pandas as pd
import numpy as np
df = pd.DataFrame({'A':['1a',np.nan,'10a','100b','0b'],
})
df
A
0 1a
1 NaN
2 10a
3 100b
4 0b
I’d like to extract the numbers from each cell (where they exist).
The desired result is:
A 0 1 1 NaN 2 10 3 100 4 0
I know it can be done with str.extract, but I’m not sure how.
Answers:
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Method 1
Give it a regex capture group:
df.A.str.extract('(d+)')
Gives you:
0 1 1 NaN 2 10 3 100 4 0 Name: A, dtype: object
Method 2
To answer @Steven G ‘s question in the comment above, this should work:
df.A.str.extract('(^d*)')
Method 3
U can replace your column with your result using “assign” function:
df = df.assign(A = lambda x: x['A'].str.extract('(d+)'))
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