Python: count repeated elements in the list

I am new to Python. I am trying to find a simple way of getting a count of the number of elements repeated in a list e.g.

MyList = ["a", "b", "a", "c", "c", "a", "c"]

Output:

a: 3
b: 1
c: 3

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

You can do that using count:

my_dict = {i:MyList.count(i) for i in MyList}

>>> print my_dict     #or print(my_dict) in python-3.x
{'a': 3, 'c': 3, 'b': 1}

Or using collections.Counter:

from collections import Counter

a = dict(Counter(MyList))

>>> print a           #or print(a) in python-3.x
{'a': 3, 'c': 3, 'b': 1}

Method 2

Use Counter

>>> from collections import Counter
>>> MyList = ["a", "b", "a", "c", "c", "a", "c"]
>>> c = Counter(MyList)
>>> c
Counter({'a': 3, 'c': 3, 'b': 1})

Method 3

This works for Python 2.6.6

a = ["a", "b", "a"]
result = dict((i, a.count(i)) for i in a)
print result

prints

{'a': 2, 'b': 1}

Method 4

yourList = ["a", "b", "a", "c", "c", "a", "c"]

expected outputs {a: 3, b: 1,c:3}

duplicateFrequencies = {}
for i in set(yourList):
    duplicateFrequencies[i] = yourList.count(i)

Cheers!! Reference

Method 5

In [2]: MyList = ["a", "b", "a", "c", "c", "a", "c"]

In [3]: count = {}

In [4]: for i in MyList:
   ...:     if not i in count:
   ...:         count[i] = 1
   ...:     else:
   ...:         count[i] +=1
   ...:

In [5]: count
Out[5]: {'a': 3, 'b': 1, 'c': 3}

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0