I have a request URI and a token. If I use:
curl -s "<MY_URI>" -H "Authorization: TOK:<MY_TOKEN>"
etc., I get a 200 and view the corresponding JSON data.
So, I installed requests and when I attempt to access this resource I get a 403 probably because I do not know the correct syntax to pass that token. Can anyone help me figure it out?
This is what I have:
import sys,socket
import requests
r = requests.get('<MY_URI>','<MY_TOKEN>')
r. status_code
I already tried:
r = requests.get('<MY_URI>',auth=('<MY_TOKEN>'))
r = requests.get('<MY_URI>',auth=('TOK','<MY_TOKEN>'))
r = requests.get('<MY_URI>',headers=('Authorization: TOK:<MY_TOKEN>'))
But none of these work.
Answers:
Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.
Method 1
In python:
('<MY_TOKEN>')
is equivalent to
'<MY_TOKEN>'
And requests interprets
('TOK', '<MY_TOKEN>')
As you wanting requests to use Basic Authentication and craft an authorization header like so:
'VE9LOjxNWV9UT0tFTj4K'
Which is the base64 representation of 'TOK:<MY_TOKEN>'
To pass your own header you pass in a dictionary like so:
r = requests.get('<MY_URI>', headers={'Authorization': 'TOK:<MY_TOKEN>'})
Method 2
I was looking for something similar and came across this. It looks like in the first option you mentioned
r = requests.get('<MY_URI>', auth=('<MY_TOKEN>'))
“auth” takes two parameters: username and password, so the actual statement should be
r=requests.get('<MY_URI>', auth=('<YOUR_USERNAME>', '<YOUR_PASSWORD>'))
In my case, there was no password, so I left the second parameter in auth field empty as shown below:
r=requests.get('<MY_URI', auth=('MY_USERNAME', ''))
Hope this helps somebody 🙂
Method 3
This worked for me:
access_token = #yourAccessTokenHere#
result = requests.post(url,
headers={'Content-Type':'application/json',
'Authorization': 'Bearer {}'.format(access_token)})
Method 4
You can also set headers for the entire session:
TOKEN = 'abcd0123'
HEADERS = {'Authorization': 'token {}'.format(TOKEN)}
with requests.Session() as s:
s.headers.update(HEADERS)
resp = s.get('http://example.com/')
Method 5
i founded here, its ok with me for linkedin:
https://auth0.com/docs/flows/guides/auth-code/call-api-auth-code
so my code with with linkedin login here:
ref = 'https://api.linkedin.com/v2/me'
headers = {"content-type": "application/json; charset=UTF-8",'Authorization':'Bearer {}'.format(access_token)}
Linkedin_user_info = requests.get(ref1, headers=headers).json()
Method 6
Requests natively supports basic auth only with user-pass params, not with tokens.
You could, if you wanted, add the following class to have requests support token based basic authentication:
import requests
from base64 import b64encode
class BasicAuthToken(requests.auth.AuthBase):
def __init__(self, token):
self.token = token
def __call__(self, r):
authstr = 'Basic ' + b64encode(('token:' + self.token).encode('utf-8')).decode('utf-8')
r.headers['Authorization'] = authstr
return r
Then, to use it run the following request :
r = requests.get(url, auth=BasicAuthToken(api_token))
An alternative would be to formulate a custom header instead, just as was suggested by other users here.
Method 7
You can try something like this
r = requests.get(ENDPOINT, params=params, headers={'Authorization': 'Basic %s' % API_KEY})
Method 8
This worked for me:
r = requests.get('http://127.0.0.1:8000/api/ray/musics/', headers={'Authorization': 'Token 22ec0cc4207ebead1f51dea06ff149342082b190'})
My code uses user generated token.
Method 9
You have a request needing an authorization maybe you have a result 401.
Suppose your request is like this :
REQ ='https://api.asite.com/something/else/else'
You have your token :
TOKEN = 'fliuzabuvdgfnsuczkncsq12454632'
build your header like this :
HEADER = {'Authorization': f'{TOKEN}'}
and use it like this :
req.get(REQ, headers=HEADER)
display your result like this :
req.get(COACH, headers=HEADER).json()
All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0