Python script for Django app to access models without using manage.py shell

I’m writing a script to import some model objects into the database my django application uses. In the past I’ve solved this by running ./manage.py shell and then import myscript. I’m sure there’s a better way. I’d like to be able to call a script from anywhere on my HD using python scriptname.py, and in the first few lines of that script it would do whatever imports / other operations necessary so that it can access model objects and behave as though it was run using manage.py shell.

What do I need to add to my script to achieve this?

EDIT:

Based on @Melug’s answer, with addition of dynamically setting Python path to address the ‘anywhere on my HD’ part of the question:

import sys
sys.path.append('c:\my_projec_src_folder')
from myproject import settings
from django.core.management import setup_environ
setup_environ(settings)

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

Since Django 1.4 you should avoid using setup_environ(settings) (post by Melug) because it is deprecated. Use the following instead and you will be able to access your model

import os

os.environ.setdefault("DJANGO_SETTINGS_MODULE", "your_project_name.settings")

# your imports, e.g. Django models
from your_project_name.models import Location

# From now onwards start your script..

Here is an example to access and modify your model:

if __name__ == '__main__':    
    # e.g. add a new location
    l = Location()
    l.name = 'Berlin'
    l.save()

    # this is an example to access your model
    locations = Location.objects.all()
    print locations

    # e.g. delete the location
    berlin = Location.objects.filter(name='Berlin')
    print berlin
    berlin.delete()

Example model:

class Location(models.Model):
    name = models.CharField(max_length=100)

Method 2

To get models loaded too, I had to combine this with this answer, otherwise I get django.core.exceptions.AppRegistryNotReady: Models aren't loaded yet

import os
os.environ.setdefault("DJANGO_SETTINGS_MODULE", "my_project.settings")
import django
django.setup()

As an extra, I add this to the __init__.py of my django projects, it will automatically discover the app name so it is copy/paste-able:

import os


def setup():
    module = os.path.split(os.path.dirname(__file__))[-1]
    os.environ.setdefault("DJANGO_SETTINGS_MODULE", "{}.settings".format(module))
    import django
    django.setup()

Then I can just do:

from <app> import setup
setup()

Method 3

For Django version 1.9 or later you can use this:

import sys
import os
import django

sys.path.append('your_project_directory')
os.environ['DJANGO_SETTINGS_MODULE'] = 'your_project.settings'
django.setup()

from yourapp.models import your_model

so you can use object as same django object:

from myapp.models. import Locations
all_locations = Locations.object.all()
first_location = Locations.object.get(id=1)
print first_location.name()
first_location.save()

Method 4

I think the best way is to create your custom management command(s). Then you can call manage.py <yourcommand> from anywhere.

Method 5

You need to setup django environment first:

from your_project import settings
from django.core.management import setup_environ
setup_environ(settings)

At last import your models, everything goes just like django.

Method 6

FOR DJANGO 1.11

Upper solutions did not work, but gave me an error:

django.core.exceptions.AppRegistryNotReady: Apps aren’t loaded yet.

For me solution from here worked out:

import os
from django.core.wsgi import get_wsgi_application

os.environ['DJANGO_SETTINGS_MODULE'] = 'myapp.settings'
application = get_wsgi_application()

Method 7

Since at least Django 1.11, your main app includes a wsgi module that does the neccessary setup on import. Assuming myproject/myproject is where your settings.py is, in your script just import:

from myproject.wsgi import application

Method 8

for django >= 2.0 it is enough to do these 2 imports

from your_project_path import settings as your_project_settings
from django.core.management import settings

then you can do just from my_app.models import MyModel

and work with your Model MyModel

Method 9

Here is the answer for Django versions > 1.4:

from django.core.management import settings
from myproject.myproject import settings as project_settings

if not settings.configured:
  settings.configure(default_settings=project_settings)

Method 10

If you get:

django.core.exceptions.AppRegistryNotReady: Models aren't loaded yet.

Try:

import os
from django.core.wsgi import get_wsgi_application

os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'myapp.settings')
application = get_wsgi_application()

Method 11

Try:

os.environ["DJANGO_SETTINGS_MODULE"] = "mysite.settings"

if os.environ.setdefault doesn’t work. (Windows 10, python3.6.4, django 2.0.3)

Method 12

As Stavros pointed out here, you can just copy the wsgi.py and put it at the beginning of you script. Besides setting up DJANGO_SETTINGS_MODULE, you also need to get the applications. Hope it helps. It works for me at django 2.1.5.

import os

from django.core.wsgi import get_wsgi_application

os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'revochem.settings')

application = get_wsgi_application()

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0