python time + timedelta equivalent

I’m trying to do something like this:

time() + timedelta(hours=1)

however, Python doesn’t allow it, apparently for good reason.

Does anyone have a simple work around?

Related:

• What is the standard way to add N seconds to datetime.time in Python?

Answers:

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Method 1

The solution is in the link that you provided in your question:

datetime.combine(date.today(), time()) + timedelta(hours=1)

Full example:

from datetime import date, datetime, time, timedelta

dt = datetime.combine(date.today(), time(23, 55)) + timedelta(minutes=30)
print dt.time()

Output:

00:25:00

Method 2

If it’s worth adding another file / dependency to your project, I’ve just written a tiny little class that extends datetime.time with the ability to do arithmetic. If you go past midnight, it just wraps around:

>>> from nptime import nptime
>>> from datetime import timedelta
>>> afternoon = nptime(12, 24) + timedelta(days=1, minutes=36)
>>> afternoon
nptime(13, 0)
>>> str(afternoon)
'13:00:00'

It’s available from PyPi as nptime (“non-pedantic time”), or on GitHub: https://github.com/tgs/nptime

The documentation is at http://tgs.github.io/nptime/

Method 3

Workaround:

t = time()
t2 = time(t.hour+1, t.minute, t.second, t.microsecond)

You can also omit the microseconds, if you don’t need that much precision.

Method 4

This is a bit nasty, but:

from datetime import datetime, timedelta

now = datetime.now().time()
# Just use January the first, 2000
d1 = datetime(2000, 1, 1, now.hour, now.minute, now.second)
d2 = d1 + timedelta(hours=1, minutes=23)
print d2.time()

Method 5

You can change time() to now() for it to work

from datetime import datetime, timedelta
datetime.now() + timedelta(hours=1)

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0