Pythonic way to print list items

I would like to know if there is a better way to print all objects in a Python list than this :

myList = [Person("Foo"), Person("Bar")]
print("n".join(map(str, myList)))
Foo
Bar

I read this way is not really good :

myList = [Person("Foo"), Person("Bar")]
for p in myList:
    print(p)

Isn’t there something like :

print(p) for p in myList

If not, my question is… why ? If we can do this kind of stuff with comprehensive lists, why not as a simple statement outside a list ?

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

Assuming you are using Python 3.x:

print(*myList, sep='n')

You can get the same behavior on Python 2.x using from __future__ import print_function, as noted by mgilson in comments.

With the print statement on Python 2.x you will need iteration of some kind, regarding your question about print(p) for p in myList not working, you can just use the following which does the same thing and is still one line:

for p in myList: print p

For a solution that uses 'n'.join(), I prefer list comprehensions and generators over map() so I would probably use the following:

print 'n'.join(str(p) for p in myList)

Method 2

I use this all the time :

#!/usr/bin/python

l = [1,2,3,7] 
print "".join([str(x) for x in l])

Method 3

[print(a) for a in list] will give a bunch of None types at the end though it prints out all the items

Method 4

For Python 2.*:

If you overload the function __str__() for your Person class, you can omit the part with map(str, …). Another way for this is creating a function, just like you wrote:

def write_list(lst):
    for item in lst:
        print str(item) 

...

write_list(MyList)

There is in Python 3.* the argument sep for the print() function. Take a look at documentation.

Method 5

Expanding @lucasg’s answer (inspired by the comment it received):

To get a formatted list output, you can do something along these lines:

l = [1,2,5]
print ", ".join('%02d'%x for x in l)

01, 02, 05

Now the ", " provides the separator (only between items, not at the end) and the formatting string '02d'combined with %x gives a formatted string for each item x – in this case, formatted as an integer with two digits, left-filled with zeros.

Method 6

To display each content, I use:

mylist = ['foo', 'bar']
indexval = 0
for i in range(len(mylist)):     
    print(mylist[indexval])
    indexval += 1

Example of using in a function:

def showAll(listname, startat):
   indexval = startat
   try:
      for i in range(len(mylist)):
         print(mylist[indexval])
         indexval = indexval + 1
   except IndexError:
      print('That index value you gave is out of range.')

Hope I helped.

Method 7

I think this is the most convenient if you just want to see the content in the list:

myList = ['foo', 'bar']
print('myList is %s' % str(myList))

Simple, easy to read and can be used together with format string.

Method 8

I recently made a password generator and although I’m VERY NEW to python, I whipped this up as a way to display all items in a list (with small edits to fit your needs…

    x = 0
    up = 0
    passwordText = ""
    password = []
    userInput = int(input("Enter how many characters you want your password to be: "))
    print("nnn") # spacing

    while x <= (userInput - 1): #loops as many times as the user inputs above
            password.extend([choice(groups.characters)]) #adds random character from groups file that has all lower/uppercase letters and all numbers
            x = x+1 #adds 1 to x w/o using x ++1 as I get many errors w/ that
            passwordText = passwordText + password[up]
            up = up+1 # same as x increase


    print(passwordText)

Like I said, IM VERY NEW to Python and I’m sure this is way to clunky for a expert, but I’m just here for another example

Method 9

Assuming you are fine with your list being printed [1,2,3], then an easy way in Python3 is:

mylist=[1,2,3,'lorem','ipsum','dolor','sit','amet']

print(f"There are {len(mylist):d} items in this lorem list: {str(mylist):s}")

Running this produces the following output:

There are 8 items in this lorem list: [1, 2, 3, ‘lorem’, ‘ipsum’,
‘dolor’, ‘sit’, ‘amet’]

Method 10

OP’s question is: does something like following exists, if not then why

print(p) for p in myList # doesn't work, OP's intuition

answer is, it does exist which is:

[p for p in myList] #works perfectly

Basically, use [] for list comprehension and get rid of print to avoiding printing None. To see why print prints None see this

Method 11

To print each element of a given list using a single line code

 for i in result: print(i)

Method 12

You can also make use of the len() function and identify the length of the list to print the elements as shown in the below example:

sample_list = ['Python', 'is', 'Easy']

for i in range(0, len(sample_list)):

      print(sample_list[i])

Reference : https://favtutor.com/blogs/print-list-python

Method 13

you can try doing this: this will also print it as a string

print(''.join([p for p in myList]))

or if you want to a make it print a newline every time it prints something

print(''.join([p+'n' for p in myList]))

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0