Given n lists with m dictionaries as their elements, I would like to produce a new list, with a joined set of dictionaries. Each dictionary is guaranteed to have a key called “index”, but could have an arbitrary set of keys beyond that. The non-index keys will never overlap across lists. For example, imagine the following two lists:
I am working on Retinal fundus images.The image consists of a circular retina on a black background. With OpenCV, I have managed to get a contour which surrounds the whole circular Retina. What I need is to crop out the circular retina from the black background.
For the following code:
I am getting an error while running this part of the code. I tried some of the existing solutions, but none of them helped.
I have a list of dicts in the following form that I generate from pandas. I want to convert it to a json format.
My purpose it to download a zip file from https://www.shareinvestor.com/prices/price_download_zip_file.zip?type=history_all&market=bursa
It is a link in this webpage https://www.shareinvestor.com/prices/price_download.html#/?type=price_download_all_stocks_bursa. Then save it into this directory "/home/vinvin/shKLSE/ (I am using pythonaywhere). Then unzip it and the csv file extract in the directory.
Trying to find a good way to set a maximum time limit for command execution latency in Selenium Python WebDriver. Ideally, something like:
in a simple list following check is trivial:
I want to filter a Pyspark DataFrame with a SQL-like IN clause, as in
from tkinter import * from PIL import ImageTk,Image root=Tk() root.title("Image Viewer") def buttonforward(image_number): global myLabel myLabel.grid_forget() myLabel = Label(image=imagelist[image_number-1]) myLabel.grid(row=0, column=0, columnspan=3) return my_img1 = ImageTk.PhotoImage(Image.open('mountain1.jpg')) my_img2 = ImageTk.PhotoImage(Image.open('mountain2.jpg')) my_img3 = ImageTk.PhotoImage(Image.open('mountain3.jpg')) my_img4 = ImageTk.PhotoImage(Image.open('mountain4.jpg')) my_img5 = ImageTk.PhotoImage(Image.open('mountain5.jpg')) myLabel = Label(image=my_img1, ).grid(row=0, column=0, columnspan=3) imagelist = [my_img1, my_img2, my_img3, my_img4, my_img5] button_back = Button(root, text='<<').grid(row=1,column=0) … Read more