I’m not sure why, but for some reason, whenever I have “region” in the file name of the output file, it gives me this error:
IOError: [Errno 22] invalid mode (‘w’) or filename: ‘pathregionlog.txt’
It does this for “region.txt”, “logregion.txt”, etc.
class writeTo:
def __init__(self, stdout, name):
self.stdout = stdout
self.log = file(name, 'w') #here is where it says the error occurs
output = os.path.abspath('pathregionlog.txt')
writer = writeTo(sys.stdout, output) #and here too
Why is this? I really would like to name my file “regionlog.txt” but it keeps coming up with that error. Is there a way around it?
Answers:
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Method 1
Use forward slashes:
'path/regionlog.txt'
Or raw strings:
r'pathregionlog.txt'
Or at least escape your backslashes:
'path\regionlog.txt'
r is a carriage return.
Another option: use os.path.join and you won’t have to worry about slashes at all:
output = os.path.abspath(os.path.join('path', 'regionlog.txt'))
Method 2
In C standard language, t, n, r are escape characters. t is a transverse to the next TAB position. n is a newline and r is a carriage return. You should use \r or /r, and you will solve the problem!
Method 3
Additionaly, Python also gives this message when trying to open a file > 50 MB from a SharePoint shared drive.
Method 4
Another simple solution is changing the “r” instances in the filename path to “R”
All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0