Selenium webdriver: How do I find ALL of an element’s attributes?

In the Python Selenium module, once I have a WebElement object I can get the value of any of its attributes with get_attribute():

foo = elem.get_attribute('href')

If the attribute named 'href' doesn’t exist, None is returned.

My question is, how can I get a list of all of the attributes that an element has? There doesn’t seem to be a get_attributes() or get_attribute_names() method.

I’m using version 2.44.0 of the Selenium module for Python.

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

It is not possible using a selenium webdriver API, but you can execute a javascript code to get all attributes:

driver.execute_script('var items = {}; for (index = 0; index < arguments[0].attributes.length; ++index) { items[arguments[0].attributes[index].name] = arguments[0].attributes[index].value }; return items;', element)

Demo:

>>> from selenium import webdriver
>>> from pprint import pprint
>>> driver = webdriver.Firefox()
>>> driver.get('https://stackoverflow.com')
>>> 
>>> element = driver.find_element_by_xpath('//div[@class="network-items"]/a')
>>> attrs = driver.execute_script('var items = {}; for (index = 0; index < arguments[0].attributes.length; ++index) { items[arguments[0].attributes[index].name] = arguments[0].attributes[index].value }; return items;', element)
>>> pprint(attrs)
{u'class': u'topbar-icon icon-site-switcher yes-hover js-site-switcher-button js-gps-track',
 u'data-gps-track': u'site_switcher.show',
 u'href': u'//stackexchange.com',
 u'title': u'A list of all 132 Stack Exchange sites'}

For completeness sake, an alternative solution would be to get the tag’s outerHTML and parse the attributes using an HTML parser. Example (using BeautifulSoup):

>>> from bs4 import BeautifulSoup
>>> html = element.get_attribute('outerHTML')
>>> attrs = BeautifulSoup(html, 'html.parser').a.attrs
>>> pprint(attrs)
{u'class': [u'topbar-icon',
            u'icon-site-switcher',
            u'yes-hover',
            u'js-site-switcher-button',
            u'js-gps-track'],
 u'data-gps-track': u'site_switcher.show',
 u'href': u'//stackexchange.com',
 u'title': u'A list of all 132 Stack Exchange sites'}

Method 2

The following gets a list of all attributes and their (sometimes translated to strings) values for me, using the PhantomJS or Chrome driver at least:

elem.get_property('attributes')[0]

To just get the names:

x.get_property('attributes')[0].keys()

Method 3

You can find using element.get_property() method.

from selenium import webdriver
from selenium.webdriver.common.by import By

driver = webdriver.Chrome()
driver.get("https://www.ultimateqa.com/complicated-page/")

logo = driver.find_element(By.XPATH, "//img[@id='logo']")
attrs=[]
for attr in logo.get_property('attributes'):
    attrs.append([attr['name'], attr['value']])
print(attrs)

Output:

[['src', 'https://www.ultimateqa.com/wp-content/uploads/2019/01/horizontal_on_transparent_by_logaster-2.png'], ['alt', 'Ultimate QA'], ['id', 'logo'], ['data-height-percentage', '100'], ['data-actual-width', '912'], ['data-actual-height', '410']]

Method 4

Here is my attempt at an answer. I do only tested it on the search box of google’s homepage. I made use of @alecxe’s answer above about ‘outerHTML’ Having obtained the html, I used a regular expression ([a-z]+-?[a-z]+_?)='?"? to match the attribute names. I think the regex would just have to be modified to match an increasing number of cases. But the essential name we need is “whatever is behind the equal sign.”

Given a webElement

def get_web_element_attribute_names(web_element):
    """Get all attribute names of a web element"""
    # get element html
    html = web_element.get_attribute("outerHTML")
    # find all with regex
    pattern = """([a-z]+-?[a-z]+_?)='?"?"""
    return re.findall(pattern, html)

Test it on the below code

import re
from selenium import webdriver

driver = webdriver.Firefox()
google = driver.get("http://www.google.com")

driver.find_element_by_link_text("English").click()
search_element = driver.find_element_by_name("q")
get_web_element_attribute_names(search_element)

output:

['class', 'id', 'maxlength', 'name', 'autocomplete', 'title', 'value', 'aria-label', 'aria-haspopup', 'role', 'aria-autocomplete', 'style', 'dir', 'spellcheck', 'type']

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0