Sharing a result queue among several processes

The documentation for the multiprocessing module shows how to pass a queue to a process started with multiprocessing.Process. But how can I share a queue with asynchronous worker processes started with apply_async? I don’t need dynamic joining or anything else, just a way for the workers to (repeatedly) report their results back to base.

import multiprocessing
def worker(name, que):
    que.put("%d is done" % name)

if __name__ == '__main__':
    pool = multiprocessing.Pool(processes=3)
    q = multiprocessing.Queue()
    workers = pool.apply_async(worker, (33, q))

This fails with:
RuntimeError: Queue objects should only be shared between processes through inheritance.
I understand what this means, and I understand the advice to inherit rather than require pickling/unpickling (and all the special Windows restrictions). But how do I pass the queue in a way that works? I can’t find an example, and I’ve tried several alternatives that failed in various ways. Help please?

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

Try using multiprocessing.Manager to manage your queue and to also make it accessible to different workers.

import multiprocessing
def worker(name, que):
    que.put("%d is done" % name)

if __name__ == '__main__':
    pool = multiprocessing.Pool(processes=3)
    m = multiprocessing.Manager()
    q = m.Queue()
    workers = pool.apply_async(worker, (33, q))

Method 2

multiprocessing.Pool already has a shared result-queue, there is no need to additionally involve a Manager.Queue. Manager.Queue is a queue.Queue (multithreading-queue) under the hood, located on a separate server-process and exposed via proxies. This adds additional overhead compared to Pool’s internal queue. Contrary to relying on Pool’s native result-handling, the results in the Manager.Queue also are not guaranteed to be ordered.

The worker processes are not started with .apply_async(), this already happens when you instantiate Pool. What is started
when you call pool.apply_async() is a new “job”. Pool’s worker-processes run the multiprocessing.pool.worker-function under the hood. This function takes care of processing new “tasks” transferred over Pool’s internal Pool._inqueue and of sending results back to the parent over the Pool._outqueue. Your specified func will be executed within multiprocessing.pool.worker. func only has to return something and the result will be automatically send back to the parent.

.apply_async() immediately (asynchronously) returns a AsyncResult object (alias for ApplyResult). You need to call .get() (is blocking) on that object to receive the actual result. Another option would be to register a callback function, which gets fired as soon as the result becomes ready.

from multiprocessing import Pool

def busy_foo(i):
    """Dummy function simulating cpu-bound work."""
    for _ in range(int(10e6)):  # do stuff
        pass
    return i

if __name__ == '__main__':

    with Pool(4) as pool:
        print(pool._outqueue)  # DEMO
        results = [pool.apply_async(busy_foo, (i,)) for i in range(10)]
        # `.apply_async()` immediately returns AsyncResult (ApplyResult) object
        print(results[0])  # DEMO
        results = [res.get() for res in results]
        print(f'result: {results}')

Example Output:

<multiprocessing.queues.SimpleQueue object at 0x7fa124fd67f0>
<multiprocessing.pool.ApplyResult object at 0x7fa12586da20>
result: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

Note: Specifying the timeout-parameter for .get() will not stop the actual processing of the task within the worker, it only unblocks the waiting parent by raising a multiprocessing.TimeoutError.


All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

0 0 votes
Article Rating
Subscribe
Notify of
guest

0 Comments
Oldest
Newest Most Voted
Inline Feedbacks
View all comments
0
Would love your thoughts, please comment.x
()
x