I can’t seem to Google it, but I want a function that does this:
Accept 3 arguments (or more, whatever):
- URL
- a dictionary of params
- POST or GET
Return me the results, and the response code.
Is there a snippet that does this?
Answers:
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Method 1
requests
https://github.com/kennethreitz/requests/
Here’s a few common ways to use it:
import requests
url = 'https://...'
payload = {'key1': 'value1', 'key2': 'value2'}
# GET
r = requests.get(url)
# GET with params in URL
r = requests.get(url, params=payload)
# POST with form-encoded data
r = requests.post(url, data=payload)
# POST with JSON
import json
r = requests.post(url, data=json.dumps(payload))
# Response, status etc
r.text
r.status_code
httplib2
https://github.com/jcgregorio/httplib2
>>> from httplib2 import Http
>>> from urllib import urlencode
>>> h = Http()
>>> data = dict(name="Joe", comment="A test comment")
>>> resp, content = h.request("http://bitworking.org/news/223/Meet-Ares", "POST", urlencode(data))
>>> resp
{'status': '200', 'transfer-encoding': 'chunked', 'vary': 'Accept-Encoding,User-Agent',
'server': 'Apache', 'connection': 'close', 'date': 'Tue, 31 Jul 2007 15:29:52 GMT',
'content-type': 'text/html'}
Method 2
Even easier: via the requests module.
import requests
get_response = requests.get(url='http://google.com')
post_data = {'username':'joeb', 'password':'foobar'}
# POST some form-encoded data:
post_response = requests.post(url='http://httpbin.org/post', data=post_data)
To send data that is not form-encoded, send it serialised as a string (example taken from the documentation):
import json post_response = requests.post(url='http://httpbin.org/post', data=json.dumps(post_data)) # If using requests v2.4.2 or later, pass the dict via the json parameter and it will be encoded directly: post_response = requests.post(url='http://httpbin.org/post', json=post_data)
Method 3
You could use this to wrap urllib2:
def URLRequest(url, params, method="GET"):
if method == "POST":
return urllib2.Request(url, data=urllib.urlencode(params))
else:
return urllib2.Request(url + "?" + urllib.urlencode(params))
That will return a Request object that has result data and response codes.
Method 4
import urllib
def fetch_thing(url, params, method):
params = urllib.urlencode(params)
if method=='POST':
f = urllib.urlopen(url, params)
else:
f = urllib.urlopen(url+'?'+params)
return (f.read(), f.code)
content, response_code = fetch_thing(
'http://google.com/',
{'spam': 1, 'eggs': 2, 'bacon': 0},
'GET'
)
[Update]
Some of these answers are old. Today I would use the requests module like the answer by robaple.
Method 5
I know you asked for GET and POST but I will provide CRUD since others may need this just in case: (this was tested in Python 3.7)
#!/usr/bin/env python3
import http.client
import json
print("n GET example")
conn = http.client.HTTPSConnection("httpbin.org")
conn.request("GET", "/get")
response = conn.getresponse()
data = response.read().decode('utf-8')
print(response.status, response.reason)
print(data)
print("n POST example")
conn = http.client.HTTPSConnection('httpbin.org')
headers = {'Content-type': 'application/json'}
post_body = {'text': 'testing post'}
json_data = json.dumps(post_body)
conn.request('POST', '/post', json_data, headers)
response = conn.getresponse()
print(response.read().decode())
print(response.status, response.reason)
print("n PUT example ")
conn = http.client.HTTPSConnection('httpbin.org')
headers = {'Content-type': 'application/json'}
post_body ={'text': 'testing put'}
json_data = json.dumps(post_body)
conn.request('PUT', '/put', json_data, headers)
response = conn.getresponse()
print(response.read().decode(), response.reason)
print(response.status, response.reason)
print("n delete example")
conn = http.client.HTTPSConnection('httpbin.org')
headers = {'Content-type': 'application/json'}
post_body ={'text': 'testing delete'}
json_data = json.dumps(post_body)
conn.request('DELETE', '/delete', json_data, headers)
response = conn.getresponse()
print(response.read().decode(), response.reason)
print(response.status, response.reason)
All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0