I have structure like this:
structure = [('a', 1), ('b', 3), ('c', 2)]
I would like to sum the integers (1+3+2) using sum() builtin method (in one line).
Any ideas?
Answers:
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Method 1
sum(n for _, n in structure)
would work.
Method 2
sum(x[1] for x in structure)
should work
Method 3
You could do
sum(zip(*structure)[1])
Method 4
Using a functional style, you could do
reduce(lambda x,y:x+y[1], structure,0)
All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0