How to subtract a day from a date?
I have a Python datetime.datetime object. What is the best way to subtract one day?
I have a Python datetime.datetime object. What is the best way to subtract one day?
What I need to do
I have a CSV dumpfile from a Blackberry IPD backup, created using IPDDump.
The date/time strings in here look something like this
(where EST is an Australian time-zone):
I have a Dataframe, df, with the following column:
I have a time in UTC from which I want the number of seconds since epoch.
I have a Python datetime object that I want to convert to unix time, or seconds/milliseconds since the 1970 epoch.
You can use the function tz_localize to make a Timestamp or DateTimeIndex timezone aware, but how can you do the opposite: how can you convert a timezone aware Timestamp to a naive one, while preserving its timezone?
Given a datetime.time value in Python, is there a standard way to add an integer number of seconds to it, so that 11:34:59 + 3 = 11:35:02, for example?
I have a date string of the form ‘2009/05/13 19:19:30 -0400’. It seems that previous versions of Python may have supported a %z format tag in strptime for the trailing timezone specification, but 2.6.x seems to have removed that.
Please what’s wrong with my code: