What is the ‘pythonic’ equivalent to the ‘fold’ function from functional programming?
What is the most idiomatic way to achieve something like the following, in Haskell:
What is the most idiomatic way to achieve something like the following, in Haskell:
Suppose I have ;
In a basic I had the next process.
In Python, how can I get all combinations of n binary values 0 and 1? For example, if n = 3, I want to have [ [0,0,0], [0,0,1], [0,1,0], [0,1,1], … [1,1,1] ] #total 2^3 combinations How can I do this? Answers: Thank you for visiting the Q&A section on Magenaut. Please note that all … Read more
My problem is I have values in a list. And I want to separate these values and send them as a separate parameter.
— I just parsed a big file and I created a list containing 42.000 strings/words. I want to query [against this list] to check if a given word/string belongs to it. So my question is:
I understand how functions like range() and zip() can be used in a for loop. However I expected range() to output a list – much like seq in the unix shell. If I run the following code:
I occasionally see the list slice syntax used in Python code like this:
I have a Python list and I want to know what’s the quickest way to count the number of occurrences of the item, '1' in this list. In my actual case, the item can occur tens of thousands of times which is why I want a fast way.