Single Line Nested For Loops
Wrote this function in python that transposes a matrix:
loops
Django template can’t loop defaultdict
Indeed, it boils down to the fact that the template language uses the same syntax for dictionary and attribute lookups.
python assign values to list elements in loop
Is this a valid python behavior? I would think that the end result should be [0,0,0] and the id() function should return identical values each iteration. How to make it pythonic, and not use enumerate or range(len(bar))?
Assigning values to variables in a list using a loop
var_list = [one, two, three] num = 1 for var in var_list: var = num num += 1 The above gives me an error that ‘one’ doesn’t exist. Can you not assign in this way? I want to assign an incrementing number for each var in the list. So I want the equivalent of one … Read more
Loop until a specific user input
I am trying to write a number guessing program as follows: def oracle(): n = ' ' print 'Start number = 50' guess = 50 #Sets 50 as a starting number n = raw_input("nnTrue, False or Correct?: ") while True: if n == 'True': guess = guess + int(guess/5) print print 'What about',guess, '?' break … Read more
How do I stop tkinter after function?
I’m having a problem stopping the ‘feed’; the cancel argument doesn’t seem to have any impact on the after method. Although “feed stopped” is printed to the console.
python: restarting a loop
i have:
Switch indexes, create the next highest number using the same exact 9 digits presented
So I received a challenge that states the following:
“Design a program that takes as input a 9 digit number where no digit appears twice and produces as output an arrangement of the same 9 digits corresponding to the next highest number. If no such number exists, the algorithm should indicate this. So for example, if the input is 781623954 the output would be 781624359.”
How to transform string of space-separated key,value pairs of unique words into a dict
I’ve got a string with words that are separated by spaces (all words are unique, no duplicates). I turn this string into list:
Python: Continuing to next iteration in outer loop
I wanted to know if there are any built-in ways to continue to next iteration in outer loop in python. For example, consider the code: