One liner: creating a dictionary from list with indices as keys
I want to create a dictionary out of a given list, in just one line. The keys of the dictionary will be indices, and values will be the elements of the list. Something like this:
python-3.x
What is the purpose of collections.ChainMap?
In Python 3.3 a ChainMap class was added to the collections module:
rounding errors in Python floor division
I know rounding errors happen in floating point arithmetic but can somebody explain the reason for this one:
building Python from source with zlib support
When building Python 3.2.3 from source on Ubuntu 12.04, the zlib module is not available.
Add an element in each dictionary of a list (list comprehension)
I have a list of dictionaries, and want to add a key for each element of this list.
I tried:
How to translate “bytes” objects into literal strings in pandas Dataframe, Python3.x?
I have a Python3.x pandas DataFrame whereby certain columns are strings which as expressed as bytes (like in Python2.x)
How to set the timezone in Django?
In my django project’s settings.py file, I have this line :
How do I convert a string into an f-string?
I was reading this blog post on Python’s new f-strings and they seem really neat. However, I want to be able to load an f-string from a string or file.
NoReverseMatch with keyword argument uidb64 with Django 2.0
I can’t understand why my code doesn’t work. Before it worked, but now, when I run the server and test, the code does not work.
Count number of words per row
I’m trying to create a new column in a DataFrame that contains the word count for the respective row. I’m looking for the total number of words, not frequencies of each distinct word. I assumed there would be a simple/quick way to do this common task, but after googling around and reading a handful of SO posts (1, 2, 3, 4) I’m stuck. I’ve tried the solutions put forward in the linked SO posts, but got lots of attribute errors back.