Accessing class variables from a list comprehension in the class definition
How do you access other class variables from a list comprehension within the class definition? The following works in Python 2 but fails in Python 3:
How do you access other class variables from a list comprehension within the class definition? The following works in Python 2 but fails in Python 3:
Suppose I have the following Button made with Tkinter in Python:
I’m making an Asteroidz clone in pygame and have two for event in pygame.event.get() loops, one for checking an exit request and wether the game should have started by pressing spacebar, then further in the game as to try and limit the player from holding spacebar down and continuously shooting. The relevent code for my check_input function, which is run once every loop, is below;
Why do I receive a syntax error when printing a string in Python 3? >>> print "hello World" File "<stdin>", line 1 print "hello World" ^ SyntaxError: invalid syntax Answers: Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please … Read more
I am using Python 3.1 on a Windows 7 machine. Russian is the default system language, and utf-8 is the default encoding. Looking at the answer to a previous question, I have attempting using the “codecs” module to give me a little luck. Here’s a few examples: >>> g = codecs.open(“C:UsersEricDesktopbeeline.txt”, “r”, encoding=”utf-8″) SyntaxError: (unicode … Read more
I have the following code in Python 3:
I want to import a function from another file in the same directory.
I’m trying to get a Python 3 program to do some manipulations with a text file filled with information. However, when trying to read the file I get the following error:
The following code gives the error UnboundLocalError: local variable ‘Var1’ referenced before assignment: Var1 = 1 Var2 = 0 def function(): if Var2 == 0 and Var1 > 0: print("Result One") elif Var2 == 1 and Var1 > 0: print("Result Two") elif Var1 < 1: print("Result Three") Var1 =- 1 function() How can I fix … Read more
TypeError: ‘str’ does not support the buffer interface suggests two possible methods to convert a string to bytes: