I’m quite new to using Django and I am trying to develop a website where the user is able to upload a number of excel files, these files are then stored in a media folder Webproject/project/media.
def upload(request):
if request.POST:
form = FileForm(request.POST, request.FILES)
if form.is_valid():
form.save()
return render_to_response('project/upload_successful.html')
else:
form = FileForm()
args = {}
args.update(csrf(request))
args['form'] = form
return render_to_response('project/create.html', args)
The document is then displayed in a list along with any other document they have uploaded, which you can click into and it will displays basic info about them and the name of the excelfile they have uploaded. From here I want to be able to download the same excel file again using the link:
<a href="/project/download" rel="nofollow noreferrer noopener" rel="nofollow noreferrer noopener"> Download Document </a>
My urls are
urlpatterns = [
url(r'^$', ListView.as_view(queryset=Post.objects.all().order_by("-date")[:25],
template_name="project/project.html")),
url(r'^(?P<pk>d+)$', DetailView.as_view(model=Post, template_name="project/post.html")),
url(r'^upload/$', upload),
url(r'^download/(?P<path>.*)$', serve, {'document root': settings.MEDIA_ROOT}),
] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
but I get the error, serve() got an unexpected keyword argument ‘document root’. can anyone explain how to fix this?
OR
Explain how I can get the uploaded files to to be selected and served using
def download(request):
file_name = #get the filename of desired excel file
path_to_file = #get the path of desired excel file
response = HttpResponse(mimetype='application/force-download')
response['Content-Disposition'] = 'attachment; filename=%s' % smart_str(file_name)
response['X-Sendfile'] = smart_str(path_to_file)
return response
Answers:
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Method 1
You missed underscore in argument document_root. But it’s bad idea to use serve in production. Use something like this instead:
import os
from django.conf import settings
from django.http import HttpResponse, Http404
def download(request, path):
file_path = os.path.join(settings.MEDIA_ROOT, path)
if os.path.exists(file_path):
with open(file_path, 'rb') as fh:
response = HttpResponse(fh.read(), content_type="application/vnd.ms-excel")
response['Content-Disposition'] = 'inline; filename=' + os.path.basename(file_path)
return response
raise Http404
Method 2
You can add “download” attribute inside your tag to download files.
<a href="/project/download" rel="nofollow noreferrer noopener" rel="nofollow noreferrer noopener" download> Download Document </a>
https://www.w3schools.com/tags/att_a_download.asp
Method 3
In view.py Implement function like,
def download(request, id):
obj = your_model_name.objects.get(id=id)
filename = obj.model_attribute_name.path
response = FileResponse(open(filename, 'rb'))
return response
Method 4
When you upload a file using FileField, the file will have a URL that you can use to point to the file and use HTML download attribute to download that file you can simply do this.
models.py
The model.py looks like this
class CsvFile(models.Model):
csv_file = models.FileField(upload_to='documents')
views.py
#csv upload
class CsvUploadView(generic.CreateView): model = CsvFile fields = ['csv_file'] template_name = 'upload.html'
#csv download
class CsvDownloadView(generic.ListView):
model = CsvFile
fields = ['csv_file']
template_name = 'download.html'
Then in your templates.
#Upload template
upload.html
<div class="container">
<form action="#" method="POST" enctype="multipart/form-data">
{% csrf_token %}
{{ form.media }}
{{ form.as_p }}
<button class="btn btn-primary btn-sm" type="submit">Upload</button>
</form>
#download template
download.html
{% for document in object_list %}
<a href="{{ document.csv_file.url }}" download class="btn btn-dark float-right">Download</a>
{% endfor %}
I did not use forms, just rendered model but either way, FileField is there and it will work the same.
Method 5
I’ve found Django’s FileField to be really helpful for letting users upload and download files. The Django documentation has a section on managing files. You can store some information about the file in a table, along with a FileField that points to the file itself. Then you can list the available files by searching the table.
Method 6
@Biswadp’s solution worked greatly for me
In your static folder, make sure to have the desired files you would like the user to download
In your HTML template, your code should look like this :
<a href="{% static 'Highlight.docx' %}"> Download </a>
Method 7
Using the below approach makes everything less secure since any user can access any user’s file.
<a href="/project/download" download> Download Document </a>
Using the below approach makes no sense since Django only handles one requests at the time (unless you are using gunicorn or something else), and believe me, the below approach takes a lot of time to complete.
def download(request, path):
file_path = os.path.join(settings.MEDIA_ROOT, path)
if os.path.exists(file_path):
with open(file_path, 'rb') as fh:
response = HttpResponse(fh.read(), content_type="application/vnd.ms-excel")
response['Content-Disposition'] = 'inline; filename=' + os.path.basename(file_path)
return response
raise Http404
So what is the optimum solution?
Use Nginx authenticated routes. When requesting a file from Nginx you can make a request to a route and depending on the HTTP response Nginx allows to denies that request. This makes it very secure and also scalable and performant.
You can ready about more here
Method 8
Simple using html like this downloads the file mentioned using static keyword
<a href="{% static 'bt.docx' %}" rel="nofollow noreferrer noopener" class="btn btn-secondary px-4 py-2 btn-sm">Download CV</a>
Method 9
1.settings.py:
MEDIA_DIR = os.path.join(BASE_DIR,'media') #Media MEDIA_ROOT = MEDIA_DIR MEDIA_URL = '/media/'
2.urls.py:
from django.conf.urls.static import static urlpatterns += static(settings.MEDIA_URL,document_root=settings.MEDIA_ROOT)
3.in template:
<a href="{{ file.url }}" download>Download File.</a>
Work and test in django >=3
for more detail use this link:
https://youtu.be/MpDZ34mEJ5Y
Method 10
I use this method:
{% if quote.myfile %}
<div class="">
<a role="button"
href="{{ quote.myfile.url }}"
download="{{ quote.myfile.url }}"
class="btn btn-light text-dark ml-0">
Download attachment
</a>
</div>
{% endif %}
Method 11
If you hafe upload your file in media than:
media
example-input-file.txt
views.py
def download_csv(request):
file_path = os.path.join(settings.MEDIA_ROOT, 'example-input-file.txt')
if os.path.exists(file_path):
with open(file_path, 'rb') as fh:
response = HttpResponse(fh.read(), content_type="application/vnd.ms-excel")
response['Content-Disposition'] = 'inline; filename=' + os.path.basename(file_path)
return response
urls.py
path('download_csv/', views.download_csv, name='download_csv'),
download.html
a href="{% url 'download_csv' %}" download=""
Method 12
-
<a href='/your-download-view/' download>Download</a> - In your view:
def download(request):
# pre-processing, authorizations, etc.
# ...
return FileResponse(open(path_to_file, 'rb'), as_attachment=True)
All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0