Sorting a dictionary by value then key

I can sort by key or value, but I need it sorted by value, then key, in one line. To explain this better I can show you my problem:

dict = {'apple': 2, 'banana': 3, 'almond':2 , 'beetroot': 3, 'peach': 4}

I want my output to be sorted descending by their value and then ascending (A-Z) by their key (alphabetically). Resulting in such a list:

With the output of: ['peach', 'banana', 'beetroot', 'almond', 'apple']

The only way I know how to do it so far is:

[v[0] for v in sorted(dict.items(), key=lambda(k,v): (v,k))]

With the output of: ['almond', 'apple', 'banana', 'beetroot', 'peach']

So it has sorted the values in ascending order and the keys alphabetically in ascending order (A-Z). So if I reverse this:

[v[0] for v in sorted(dict.items(), key=lambda(k,v): (v,k), reverse=True)]

With the output of: ['peach', 'beetroot', 'banana', 'apple', 'almond']

It has sorted the values in descending order and the keys alphabetically in descending order (Z-A).

Is there a way I can sort the values in descending order and the keys in ascending order (i.e. A-Z) and get the output I showed above?

Answers:

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Method 1

You need to take advantage of the fact that the values are numbers.

>>> [v[0] for v in sorted(d.iteritems(), key=lambda(k, v): (-v, k))]
['peach', 'banana', 'beetroot', 'almond', 'apple']

Method 2

To sort by descending value is, for negatable quantities, to sort by ascending negative-of-value.

[v[0] for v in sorted(dict.items(), key=lambda(k,v): (-v,k))]

Method 3

>>> d = {'apple':2, 'banana':3, 'almond':2, 'beetroot':3, 'peach':4}
>>> [k for k, v in sorted(d.iteritems(), key=lambda(k, v): (-v, k))]
['peach', 'banana', 'beetroot', 'almond', 'apple']

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0