In python, I am trying to replace a single backslash (“”) with a double backslash(“”). I have the following code:
directory = string.replace("C:UsersJoshDesktop20130216", "", "\")
However, this gives an error message saying it doesn’t like the double backslash. Can anyone help?
Answers:
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Method 1
No need to use str.replace or string.replace here, just convert that string to a raw string:
>>> strs = r"C:UsersJoshDesktop20130216"
^
|
notice the 'r'
Below is the repr version of the above string, that’s why you’re seeing \ here.
But, in fact the actual string contains just '' not \.
>>> strs 'C:\Users\Josh\Desktop\20130216' >>> s = r"fo" >>> s #repr representation 'f\o' >>> len(s) #length is 3, as there's only one `''` 3
But when you’re going to print this string you’ll not get '\' in the output.
>>> print strs C:UsersJoshDesktop20130216
If you want the string to show '\' during print then use str.replace:
>>> new_strs = strs.replace('\','\\')
>>> print new_strs
C:\Users\Josh\Desktop\20130216
repr version will now show \\:
>>> new_strs 'C:\\Users\\Josh\\Desktop\\20130216'
Method 2
Let me make it simple and clear. Lets use the re module in python to escape the special characters.
Python script :
import re s = "C:UsersJoshDesktop" print s print re.escape(s)
Output :
C:UsersJoshDesktop C:\Users\Josh\Desktop
Explanation :
Now observe that re.escape function on escaping the special chars in the given string we able to add an other backslash before each backslash, and finally the output results in a double backslash, the desired output.
Hope this helps you.
Method 3
Use escape characters: "full\path\here", "\" and "\\"
Method 4
In python (backslash) is used as an escape character. What this means that in places where you wish to insert a special character (such as newline), you would use the backslash and another character (n for newline)
With your example string you would notice that when you put "C:UsersJoshDesktop20130216" in the repl you will get "C:\Users\Josh\Desktopx8130216". This is because 2 has a special meaning in a python string. If you wish to specify then you need to put two \ in your string.
"C:\Users\Josh\Desktop\28130216"
The other option is to notify python that your entire string must NOT use as an escape character by pre-pending the string with r
r"C:UsersJoshDesktop20130216"
This is a “raw” string, and very useful in situations where you need to use lots of backslashes such as with regular expression strings.
In case you still wish to replace that single with \ you would then use:
directory = string.replace(r"C:UsersJoshDesktop20130216", "\", "\\")
Notice that I am not using r' in the last two strings above. This is because, when you use the r' form of strings you cannot end that string with a single
Why can’t Python’s raw string literals end with a single backslash?
Method 5
The backslash indicates a special escape character. Therefore, directory = path_to_directory.replace("", "\") would cause Python to think that the first argument to replace didn’t end until the starting quotation of the second argument since it understood the ending quotation as an escape character.
directory=path_to_directory.replace("\","\\")
Method 6
Maybe a syntax error in your case,
you may change the line to:
directory = str(r"C:UsersJoshDesktop20130216").replace('\','\\')
which give you the right following output:
C:\Users\Josh\Desktop\20130216
Method 7
Given the source string, manipulation with os.path might make more sense, but here’s a string solution;
>>> s=r"C:UsersJoshDesktop\20130216"
>>> '\\'.join(filter(bool, s.split('\')))
'C:\\Users\\Josh\\Desktop\\20130216'
Note that split treats the \ in the source string as a delimited empty string. Using filter gets rid of those empty strings so join won’t double the already doubled backslashes. Unfortunately, if you have 3 or more, they get reduced to doubled backslashes, but I don’t think that hurts you in a windows path expression.
Method 8
You could use
os.path.abspath(path_with_backlash)
it returns the path with
Method 9
Use:
string.replace(r"C:UsersJoshDesktop20130216", "\", "\")
Escape the character.
All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0