I have two files in these formats:
file1 :
air smell hand dude road cat
file 2:
air,4,21,01,13,3,2 smell,21,4,2,5,6 dude,1,31,42,1 road,1,4,2,1,4 cat,1,5,6,3,1 hand,1,4,2,1,6 mouse,1,3,5,6,2
what I want to do is print the entire row of file 2, if the first string in column 1 of file 2 is found in file 1, and I want to keep the order of file 1.
expected output:
air,4,21,01,13,3,2 smell,21,4,2,5,6 hand,1,4,2,1,6 dude,1,31,42,1 road,1,4,2,1,4 cat,1,5,6,3,1
Answers:
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Method 1
This should do it:
awk -F, 'FNR==NR {a[$1]; next}; $1 in a' file1 file2
edit:
Interpreted the wrong file for the ordering. A new attempt (requires gawk if that is acceptable)
gawk -F, '
FNR==NR {a[NR]=$1; next};
{b[$1]=$0}
END{for (i in a) if (a[i] in b) print b[a[i]]}
' file1 file2
edit 2:
With nowmal awk, and swapping the files around:
awk -F, 'FNR==NR {a[$1]=$0; next}; $1 in a {print a[$1]}' file2 file1
Method 2
join -t, -1 2 -2 1 <(nl -s, -ba -nrz file1 | sort -t, -k2) <(sort -t, -k1 file2) | sort -t, -k2 | cut -d, -f1,3-
The lines in file1 are numbered and the result is sorted on 2nd field. This is then joined with file2 (sorted on 1st field):
air,000001,4,21,01,13,3,2 cat,000006,1,5,6,3,1 dude,000004,1,31,42,1 hand,000003,1,4,2,1,6 road,000005,1,4,2,1,4 smell,000002,21,4,2,5,6
the result is then sorted on 2nd field (i.e. the line numbers) to restore the original line order and then the same 2nd field is removed with cut:
air,4,21,01,13,3,2 smell,21,4,2,5,6 hand,1,4,2,1,6 dude,1,31,42,1 road,1,4,2,1,4 cat,1,5,6,3,1
Method 3
You can use the simple grep command.
grep -f file1 file2
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