i would like a python library function that translates/converts across different parts of speech. sometimes it should output multiple words (e.g. “coder” and “code” are both nouns from the verb “to code”, one’s the subject the other’s the object)
# :: String => List of String
print verbify('writer') # => ['write']
print nounize('written') # => ['writer']
print adjectivate('write') # => ['written']
i mostly care about verbs <=> nouns, for a note taking program i want to write. i.e. i can write “caffeine antagonizes A1” or “caffeine is an A1 antagonist” and with some NLP it can figure out they mean the same thing. (i know that’s not easy, and that it will take NLP that parses and doesn’t just tag, but i want to hack up a prototype).
similar questions …
Converting adjectives and adverbs to their noun forms
(this answer only stems down to the root POS. i want to go between POS.)
ps called Conversion in linguistics http://en.wikipedia.org/wiki/Conversion_%28linguistics%29
Answers:
Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.
Method 1
This is more a heuristic approach. I have just coded it so appologies for the style. It uses the derivationally_related_forms() from wordnet. I have implemented nounify. I guess verbify works analogous. From what I’ve tested works pretty well:
from nltk.corpus import wordnet as wn
def nounify(verb_word):
""" Transform a verb to the closest noun: die -> death """
verb_synsets = wn.synsets(verb_word, pos="v")
# Word not found
if not verb_synsets:
return []
# Get all verb lemmas of the word
verb_lemmas = [l for s in verb_synsets
for l in s.lemmas if s.name.split('.')[1] == 'v']
# Get related forms
derivationally_related_forms = [(l, l.derivationally_related_forms())
for l in verb_lemmas]
# filter only the nouns
related_noun_lemmas = [l for drf in derivationally_related_forms
for l in drf[1] if l.synset.name.split('.')[1] == 'n']
# Extract the words from the lemmas
words = [l.name for l in related_noun_lemmas]
len_words = len(words)
# Build the result in the form of a list containing tuples (word, probability)
result = [(w, float(words.count(w))/len_words) for w in set(words)]
result.sort(key=lambda w: -w[1])
# return all the possibilities sorted by probability
return result
Method 2
Here is a function that is in theory able to convert words between noun/verb/adjective/adverb form that I updated from here (originally written by bogs, I believe) to be compliant with nltk 3.2.5 now that synset.lemmas and sysnset.name are functions.
from nltk.corpus import wordnet as wn
# Just to make it a bit more readable
WN_NOUN = 'n'
WN_VERB = 'v'
WN_ADJECTIVE = 'a'
WN_ADJECTIVE_SATELLITE = 's'
WN_ADVERB = 'r'
def convert(word, from_pos, to_pos):
""" Transform words given from/to POS tags """
synsets = wn.synsets(word, pos=from_pos)
# Word not found
if not synsets:
return []
# Get all lemmas of the word (consider 'a'and 's' equivalent)
lemmas = []
for s in synsets:
for l in s.lemmas():
if s.name().split('.')[1] == from_pos or from_pos in (WN_ADJECTIVE, WN_ADJECTIVE_SATELLITE) and s.name().split('.')[1] in (WN_ADJECTIVE, WN_ADJECTIVE_SATELLITE):
lemmas += [l]
# Get related forms
derivationally_related_forms = [(l, l.derivationally_related_forms()) for l in lemmas]
# filter only the desired pos (consider 'a' and 's' equivalent)
related_noun_lemmas = []
for drf in derivationally_related_forms:
for l in drf[1]:
if l.synset().name().split('.')[1] == to_pos or to_pos in (WN_ADJECTIVE, WN_ADJECTIVE_SATELLITE) and l.synset().name().split('.')[1] in (WN_ADJECTIVE, WN_ADJECTIVE_SATELLITE):
related_noun_lemmas += [l]
# Extract the words from the lemmas
words = [l.name() for l in related_noun_lemmas]
len_words = len(words)
# Build the result in the form of a list containing tuples (word, probability)
result = [(w, float(words.count(w)) / len_words) for w in set(words)]
result.sort(key=lambda w:-w[1])
# return all the possibilities sorted by probability
return result
convert('direct', 'a', 'r')
convert('direct', 'a', 'n')
convert('quick', 'a', 'r')
convert('quickly', 'r', 'a')
convert('hunger', 'n', 'v')
convert('run', 'v', 'a')
convert('tired', 'a', 'r')
convert('tired', 'a', 'v')
convert('tired', 'a', 'n')
convert('tired', 'a', 's')
convert('wonder', 'v', 'n')
convert('wonder', 'n', 'a')
As you can see below, it doesn’t work so great. It’s unable to switch between adjective and adverb form (my specific goal), but it does give some interesting results in other cases.
>>> convert('direct', 'a', 'r')
[]
>>> convert('direct', 'a', 'n')
[('directness', 0.6666666666666666), ('line', 0.3333333333333333)]
>>> convert('quick', 'a', 'r')
[]
>>> convert('quickly', 'r', 'a')
[]
>>> convert('hunger', 'n', 'v')
[('hunger', 0.75), ('thirst', 0.25)]
>>> convert('run', 'v', 'a')
[('persistent', 0.16666666666666666), ('executive', 0.16666666666666666), ('operative', 0.16666666666666666), ('prevalent', 0.16666666666666666), ('meltable', 0.16666666666666666), ('operant', 0.16666666666666666)]
>>> convert('tired', 'a', 'r')
[]
>>> convert('tired', 'a', 'v')
[]
>>> convert('tired', 'a', 'n')
[('triteness', 0.25), ('banality', 0.25), ('tiredness', 0.25), ('commonplace', 0.25)]
>>> convert('tired', 'a', 's')
[]
>>> convert('wonder', 'v', 'n')
[('wonder', 0.3333333333333333), ('wonderer', 0.2222222222222222), ('marveller', 0.1111111111111111), ('marvel', 0.1111111111111111), ('wonderment', 0.1111111111111111), ('question', 0.1111111111111111)]
>>> convert('wonder', 'n', 'a')
[('curious', 0.4), ('wondrous', 0.2), ('marvelous', 0.2), ('marvellous', 0.2)]
hope this is able to save someone a little trouble
Method 3
I understand that this doesn’t answer your whole question, but it does answer a large part of it. I would check out
http://nodebox.net/code/index.php/Linguistics#verb_conjugation
This python library is able to conjugate verbs, and recognize whether a word is a verb, noun, or adjective.
EXAMPLE CODE
print en.verb.present("gave")
print en.verb.present("gave", person=3, negate=False)
>>> give
>>> gives
It can also categorize words.
print en.is_noun("banana")
>>> True
The download is at the top of the link.
Method 4
One approach may be to use a dictionary of words with their POS tags and a wordforms mapping. If you get or create such dictionary (which is quite possible if you have access to any conventional dictionary’s data, as all the dictionaries list word’s POS tags, as well as base forms for all derived forms), you can use something like the following:
def is_verb(word):
if word:
tags = pos_tags(word)
return 'VB' in tags or 'VBP' in tags or 'VBZ' in tags
or 'VBD' in tags or 'VBN' in tags:
def verbify(word):
if is_verb(word):
return word
else:
forms = []
for tag in pos_tags(word):
base = word_form(word, tag[:2])
if is_verb(base):
forms.append(base)
return forms
All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0