Extract a string between double quotes

I’m reading a response from a source which is an journal or an essay and I have the html response as a string like:

According to some, dreams express “profound aspects of personality” (Foulkes 184), though others disagree.

My goal is just to extract all of the quotes out of the given string and save each of them into a list. My approach was:

[match.start() for m in re.Matches(inputString, ""([^"]*)""))]

Somehow it didn’t work for me. Any helps on my regex here? Thanks a lot.

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Answers:

Method 1

Method 2

Answers:

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Method 1

Provided there are no nested quotes:

re.findall(r'"([^"]*)"', inputString)

Demo:

>>> import re
>>> inputString = 'According to some, dreams express "profound aspects of personality" (Foulkes 184), though others disagree.'
>>> re.findall(r'"([^"]*)"', inputString)
['profound aspects of personality']

Method 2

Use this one if your input can have something like this: some "text " and text" more

s = '''According to some, dreams express "profound aspects of personality" (Foulkes 184), though others disagree.'''
lst = re.findall(r'"(.*?)(?<!\)"', s)
print lst

Using (?<!\) negative lookbehind it is checking there is no before the "

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0

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