Get the string within brackets in Python

I have a sample string <alpha.Customer[cus_Y4o9qMEZAugtnW] active_card=<alpha.AlphaObject[card] ...>, created=1324336085, description='Customer for My Test App', livemode=False>

I only want the value cus_Y4o9qMEZAugtnW and NOT card (which is inside another [])

How could I do it in easiest possible way in Python?
Maybe by using RegEx (which I am not good at)?

Answers:

Thank you for visiting the Q&A section on Magenaut. Please note that all the answers may not help you solve the issue immediately. So please treat them as advisements. If you found the post helpful (or not), leave a comment & I’ll get back to you as soon as possible.

Method 1

How about:

import re

s = "alpha.Customer[cus_Y4o9qMEZAugtnW] ..."
m = re.search(r"[([A-Za-z0-9_]+)]", s)
print m.group(1)

For me this prints:

cus_Y4o9qMEZAugtnW

Note that the call to re.search(...) finds the first match to the regular expression, so it doesn’t find the [card] unless you repeat the search a second time.

Edit: The regular expression here is a python raw string literal, which basically means the backslashes are not treated as special characters and are passed through to the re.search() method unchanged. The parts of the regular expression are:

1. [ matches a literal [ character
2. ( begins a new group
3. [A-Za-z0-9_] is a character set matching any letter (capital or lower case), digit or underscore
4. + matches the preceding element (the character set) one or more times.
5. ) ends the group
6. ] matches a literal ] character

Edit: As D K has pointed out, the regular expression could be simplified to:

m = re.search(r"[(w+)]", s)

since the w is a special sequence which means the same thing as [a-zA-Z0-9_] depending on the re.LOCALE and re.UNICODE settings.

Method 2

You could use str.split to do this.

s = "<alpha.Customer[cus_Y4o9qMEZAugtnW] active_card=<alpha.AlphaObject[card]
 ...>, created=1324336085, description='Customer for My Test App',
 livemode=False>"
val = s.split('[', 1)[1].split(']')[0]

Then we have:

>>> val
'cus_Y4o9qMEZAugtnW'

Method 3

This should do the job:

re.match(r"[^[]*[([^]]*)]", yourstring).groups()[0]

Method 4

your_string = "lnfgbdgfi343456dsfidf[my data] ljfbgns47647jfbgfjbgskj"
your_string[your_string.find("[")+1 : your_string.find("]")]

courtesy: Regular expression to return text between parenthesis

Method 5

You can also use

re.findall(r"[([A-Za-z0-9_]+)]", string)

if there are many occurrences that you would like to find.

See also for more info:
How can I find all matches to a regular expression in Python?

Method 6

You can use

import re

s = re.search(r"[.*?]", string)
if s:
    print(s.group(0))

Method 7

How about this ? Example illusrated using a file:

f = open('abc.log','r')
content = f.readlines()
for line in content:
    m = re.search(r"[(.*?)]", line)
    print m.group(1)

Hope this helps:

Magic regex : [(.*?)]

Explanation:

[ : [ is a meta char and needs to be escaped if you want to match it literally.

(.*?) : match everything in a non-greedy way and capture it.

] : ] is a meta char and needs to be escaped if you want to match it literally.

Method 8

This snippet should work too, but it will return any text enclosed within “[]”

re.findall(r"[([a-zA-Z0-9 ._]*)]", your_text)

All methods was sourced from stackoverflow.com or stackexchange.com, is licensed under cc by-sa 2.5, cc by-sa 3.0 and cc by-sa 4.0