Say I have folder “foo” residing, the home directory. I want to get some info of it, owner, group, permissions, etc…
I then do this to try to get the information:
cd ~ ls -l foo
Of course it now lists the info of the contents of “foo”
Then I could do something like this
cd ~
dir=foo
ls -l $foo/.. | awk 'BEGIN { dir="'$foo'" } { if($9 == dir) { print $0 } }'
But isn’t there an easier way to do this?
Answers:
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Method 1
Try
ls -ld foo
And you will get what you want.
But also consider stat if you want to capture information. The output of ls is for human consumption only.
stat -c %U foo # get owner of foo
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