How do i make this script print out multiple boxes?

I have this script that prints out a box frame with Asterisk signs, and I need to make it so that the script prints out multiple boxes under each other. How can I do it?

#!/bin/bash
#
echo -n "Please enter the amount of lines: "
read lines
echo -n "Please enter the amount of *: "
read sign
for((i = 1; i <= $lines; i++))
do
  echo -n "$i "
  if [ $i -eq 1 -o $i -eq $lines ]; then
  for((j = 1; j <= $sign; j++))
  do
    echo -n "* "
  done

  else
    echo -n "* "
    for((j = 2; j < $sign; j++))
    do
      echo -n "  "
    done
    echo -n "* "
  fi
  echo
done
#end

Answers:

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Method 1

If you just want the number of boxes as an input, it is just:

#!/bin/bash
#
echo -n "Please enter the amount of lines: "
read lines
echo -n "Please enter the amount of *: "
read sign
echo -n "Please enter the amount of boxes: "
read boxes
for ((h = 1; h <= $boxes; h++))
do
    for((i = 1; i <= $lines; i++))
    do
        echo -n "$i "
        if [ $i -eq 1 -o $i -eq $lines ]; then
            for((j = 1; j <= $sign; j++))
            do
                echo -n "* "
            done
        else
            echo -n "* "
            for((j = 2; j < $sign; j++))
            do
                echo -n "  "
            done
            echo -n "* "
        fi
        echo
    done
done
#end

Not sure whether this is what you want though, because if you wrote your code you should have probably figured it out.

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